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kodGreya [7K]
3 years ago
13

Two tugboats pull a disabled supertanker. Each tug exerts a constant force of 1.60×106 N, one at an angle 13.0 west of north, an

d the other at an angle 13.0 east of north, as they pull the tanker a distance 0.700 km toward the north.
What is the total work done by the two tugboats on the supertanker?

Express your answer in joules, to three significant figures.

Physics
1 answer:
Juliette [100K]3 years ago
3 0

Answer:W=1.93\times 10^9 J      

Explanation:

Given

Force F=1.6\times 10^{6} N

one at an angle of 13^{\circ} East of North and another at 13^{\circ} West of North

Net Force is in North Direction

F_{net}=2F\cos 13

Forces in horizontal direction will cancel out each other

thus Work done will be by north direction forces  

W=2F\cdot \cos 30\cdot s

here s=0.7 km

W=2\times 1.6\times 10^{6}\cdot \cos 30\cdot 700

W=1.93\times 10^9 J                  

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The gravitational force between two objects has a magnitude of F. If both masses were doubled and the distance between them doub
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Answer:

F' = F

Explanation:

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F = \frac{Gm_1m_2}{r^2}

where,

F = Force of attraction

G = Universal gravitational costant

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m₂ = mass of second object

r = distance between objects

Now, if the masses and the distance between them is doubled:

F' = \frac{G(2m_1)(2m_2)}{(2r)^2}\\\\F' = \frac{Gm_1m_2}{r^2}

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A ball is thrown so that its initial vertical and horizontal components of velocity are 30 m/s and 15 m/s, respectively. Estimat
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Answer:

H = 45 m

Explanation:

First we find the launch velocity of the ball by using the following formula:

v₀ = √(v₀ₓ² + v₀y²)

where,

v₀ = launching velocity = ?

v₀ₓ = Horizontal Component of Launch Velocity = 15 m/s

v₀y = Vertical Component of Launch Velocity = 30 m/s

Therefore,

v₀ = √[(15 m/s)² + (30 m/s)²]

v₀ = 33.54 m/s

Now, we find the launch angle of the ball by using the following formula:

θ = tan⁻¹ (v₀y/v₀ₓ)

θ = tan⁻¹ (30/15)

θ = tan⁻¹ (2)

θ = 63.43°

Now, the maximum height attained by the ball is given by the formula:

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H = (33.54 m/s)² (Sin² 63.43°)/2(10 m/s²)

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Answer: Number of valence electrons determine how fast or easy for an atom to gain stability. Either by gaining electrons or by losing electrons.

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All the elements in a particular group will have the same number of valence electrons as follows:

Group one - 1 valence electron

Group two - 2 valence electrons

Group three - 3 valence electrons

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Group five - 3 valence electrons

Group six - 2 valence electrons

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Group eight - 0 valence electron

Some elements are more reactive than the others because of the electron affinity, oxidation state and electronegativity of the atoms

For instance, elements in group 7 are more reactive than others because of their oxidation state and they have very high electronegativity.

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