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g100num [7]
2 years ago
15

In a building with 10.000 cubic feet where the air changes every two hours, what the rate of air change? A. 167.7 cfm B. 83.3 cf

m C. 133.3 cfm D. 50 cfm
Physics
2 answers:
stepladder [879]2 years ago
3 0

Answer:

B. 83.3 cfm

Explanation:

given that the rate of change is,

= 10000 ft³ per 2 hour  (note 2 hours = 60 min x 2 = 120 min)

=  10000 ft³ per 120 min

= 10000 / 120  ft³ per min

= 83.3 ft³ per min

PolarNik [594]2 years ago
3 0
The answer is b I hope it helps
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Emmy is standing on a moving sidewalk that moves at +2 m/s. Suddenly, she realizes she might miss her flight, so begins to speed
likoan [24]

Answer:

Refer to the attachment for the diagram.

3.53 m/s.

Explanation:

Acceleration is the first derivative of velocity relative to time. In other words, the acceleration is the same as the slope (gradient) of the velocity-time graph. Let t represents the time in seconds and v the speed in meters-per-second.

For 0 < x \le 1:

  • Initial value of v: \rm 2\;m\cdot s^{-1} at t = 0; Hence the point on the segment: (0, 2).
  • Slope of the velocity-time graph is the same as acceleration during that period of time: \rm 2\; m\cdot s^{-2}.
  • Find the equation of this segment in slope-point form: v - 2 = 2 (t - 0) \implies v = 2t + 2, \quad 0 < t \le 1.

Similarly, for 1 < x \le 2:

  • Initial value of v is the same as the final value of v in the previous equation at t = 1: t = 2t + 2 = 4; Hence the point on the segment: (1, 4).
  • Slope of the velocity-time graph is the same as acceleration during that period of time: \rm 1\; m\cdot s^{-2}.
  • Find the equation of this segment in slope-point form: v - 4 = (t - 1) \implies v = t + 3 \quad 1 < t \le 2.

For 2 < x \le 3:

  • Initial value of v is the same as the final value of v in the previous equation at t = 2: t = t + 3 = 5; Hence the point on the segment: (2, 5).
  • Slope of the velocity-time graph is the same as acceleration during that period of time: \rm 0\; m\cdot s^{-2}. There's no acceleration. In other words, the velocity is constant.
  • Find the equation of this segment in slope-point form: v - 5 = 0 (t - 2) \implies v = 5 \quad 2 < t \le 3.

For 3 < x \le 4:

  • Initial value of v is the same as the final value of v in the previous equation at t = 3: t = 5; Hence the point on the segment: (3, 5).
  • Slope of the velocity-time graph is the same as acceleration during that period of time: \rm -3\; m\cdot s^{-2}. In other words, the velocity is decreasing.
  • Find the equation of this segment in slope-point form: v - 5 = -3 (t - 3) \implies v = -3t + 14 \quad 3 < t \le 4.

For 4 < x \le 5:

  • Initial value of v is the same as the final value of v in the previous equation at t = 4: t = -3t + 14; Hence the point on the segment: (4, 2).
  • Slope of the velocity-time graph is the same as acceleration during that period of time: \rm 0\; m\cdot s^{-2}. In other words, the velocity is once again constant.
  • Find the equation of this segment in slope-point form: v - 2 = 0 (t - 4) \implies v = 2\quad 4 < t \le 5.

t = \rm 3.49\;s is in the interval 3 < x \le 4. Apply the equation for that interval: v = -3t +14 = \rm 3.53\; m \cdot s^{-1}.

4 0
3 years ago
Explain what is meant by “In Phase” and “Out of Phase?
LekaFEV [45]
In phase would mean both waves are at a positive peak, out of phase would mean one is at a positive whilst the other is at a negative. Out of phase would mean the waves cancel each other out
5 0
3 years ago
Read 2 more answers
Groups of organs that work together to complete a process in the body are called:
Ainat [17]

Answer:

systems

Explanation:

they are a bunch of things functioning together

3 0
3 years ago
Read 2 more answers
Which weather event is capable of destroying homes and uprooting trees due to a low pressure area at its center
Bond [772]

You're talking about a <em>tornado</em>.

It's not so much the low pressure that's so dangerous in the center of a tornado.  It's more a matter of the high winds that are <em>caused </em>by the low pressure.

7 0
3 years ago
Read 2 more answers
Name:
Brums [2.3K]

Answer:

1.a) 1 kJ

1.b) 4 kJ

     ratio 1:4

1.c) 4 times as before

2.a)  3.33 m/s2

Explanation:

1.a) bicycle's velocity =Displacement/time

                                   =100/20 m/s

                                   =5 m/s

bicycler's KE =1/2 *mass*(velocity)^2

                      =1/2*80*5^2

                       =1000 J = 1 kJ

1.b) bicycle's new velocity =200/20 m/s

                                   =10 m/s

bicycler's new KE =1/2*80*10^2

                             =4000 J = 4 kJ

Ratio= KE 1 :KE new

        = 1 :4

1.c)  when bicycler's speed was doubled it increased the KE by 4 times (2^2). because In KE we consider the square of the speed , so the factor we increase the speed , the KE will get increased with the square value of it

ex : speed is triple the prior value , then the KE is as 3^2 times as before. that is 9 times

2.a) car acceleration = (20-0)/6 m/s2

                                  = 3.33 m/s2

4 0
3 years ago
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