All categories

3 years ago

I’m not sure how to determine the answer to this, I specifically need help with B.

Physics

1 answer:

galina1969 [7]3 years ago

8 0

Answer:

B. From positions A and D.

Explanation:

<u>Types Of Energy Transfers</u>

Heat can be transferred in three ways: by conduction, convection, and by radiation.

Conduction is the transfer of energy from one molecule to another by direct contact.

Convection is the movement of heat by a fluid such as water or air.

Radiation is the transfer of heat by electromagnetic waves.

You might be interested in

Need help on this please

Sunny_sXe [5.5K]

That part of the wave is called a compression.

8 0

4 years ago

Read 2 more answers

A ball of mass 45kg thrown upward with a velocity of 40m/s

AnnyKZ [126]

1) KE=1/2*m*v^2
1/2*45*40^2
KE=36,000J

2) PE=mgh
45*9.81*30
PE=13243.5J

4 0

3 years ago

An automobile battery has an emf of 12.6 V and an internal resistance of 0.0600 . The headlights together present equivalent res

murzikaleks [220]

Answer:

(a) $V=11.86\ V$

(b) $V=9.76\ V$

Explanation:

<u>Electric Circuits</u>

Suppose we have a resistive-only electric circuit. The relation between the current I and the voltage V in a resistance R is given by the Ohm's law:

$V=R.I$

(a) The electromagnetic force of the battery is $\varepsilon =12.6\ V$ and its internal resistance is $R_i=0.06\ \Omega$ . Knowing the equivalent resistance of the headlights is $R_e=5.2\ \Omega$ , we can compute the current of the circuit by using the Kirchhoffs Voltage Law or KVL:

$\varepsilon=i.R_i+i.R_e=i.(R_i+R_e)$

Solving for i

$\displaystyle i=\frac{\varepsilon}{ R_i+R_e}=\frac{12}{0.06+5.2}=2.28\ A$

i=2.28\ A

The potential difference across the headlight bulbs is

$V=\varepsilon -i.R_i=12\ V-2.28\ A\cdot 0.06\ \Omega=11.86\ V$

$V=11.86\ V$

(b) If the starter motor is operated, taking an additional 35 Amp from the battery, then the total load current is 2.28 A + 35 A = 37.28 A. Thus the output voltage of the battery, that is the voltage that the bulbs have is

$V=\varepsilon -i.R_i=12\ V-37.28\ A\cdot 0.06\ \Omega=9.76\ V$

5 0

3 years ago

How you can prevent thermal energy from moving by conduction, convection, and radiation?

Vanyuwa [196]

Answer:

Using insulating materials is the best way to prevent heat transfer by conduction and convection. Insulating materials are poor conductors of thermal energy and also limit the movement of air in spaces, reducing convection. Insulation slows the rate at which unwanted energy enters the home in the summer.

Explanation:

Easy peasy.

5 0

3 years ago

Read 2 more answers

When you talk about a battery's voltage, you are referring to

stich3 [128]

How powerful it is :)

8 0

3 years ago