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3 years ago

70.5

Physics

1 answer:

ra1l [238]3 years ago

5 0

Answer:5000000000hertz

Explanation:

Wavelength=6cm=6/100 m=0.06m

Frequency=velocity/wavelength

Frequency=(3×10^8)÷0.06

Frequency=5000000000 hertz

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After four half-lives of decay, what is the ratio of radioactive parent isotope to stable daughter isotope?

Margarita [4]

Answer:

Ratio of parent to daughter nuclei is 16 : 1

1 : 0.0625

Explanation:

The half of a radioisotope is the time it will take half of the original mass to decay.

Let the original mass be y

After the first half life, the new mass will be y/2

After the second half decay, the new mass will be y/4

After the third half decay, the new mass will be y/8

After the fourth half life decay, the new mass will be y/16.

Thus the ratio of the mother nucleus to the daughter nucleus will be y : y/16

Multiply the ratio through by 16

= 16y : y

= 16 : 1

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Answer: As a red photon has a twice of the wavelegth to the violet photon then the red photon has half energy of the violet photon.

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so the energy of photons are inversely proportional to the wavelength.

As a consequence twice wavelengtht means half energy for the photon.

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3 years ago

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3 years ago

Read 2 more answers

A diver shines a flashlight upward from beneath the water (n = 1.33) at a 32.7° angle to the vertical. At what angle does the li

suter [353]

Answer:

45.93°

Explanation:

The angle of incidence is given as 32.7°

The refractive index of the water that is $n_1=1.33$

Refractive index of the air that is $n_2=1$ (because the refractive index of air is 1 )

We have to find the angle at which the light leave the water means angle of refraction

So according to snell's law $n_1sini=n_2sinr$

$1.33sin32.7=1\times sinr$

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3 years ago

An atom of uranium 238 emits an alpha particle (an atom of He) and recoils with a velocity of 1.895 * 10^ 5 m/sec . With velocit

lora16 [44]

<u>Answer:</u> The velocity of released alpha particle is $1.127\times 10^7m/s$

<u>Explanation:</u>

According to law of conservation of momentum, momentum can neither be created nor be destroyed until and unless, an external force is applied.

For a system:

$m_1v_1=m_2v_2$

where,

$m_1\text{ and }v_1$ = Initial mass and velocity

$m_2\text{ and }v_2$ = Final mass and velocity

We are given:

$m_1=238u\\v_1=1.895\times 10^{5}m/s\\m_2=4u\text{ (Mass of }\alpha \text{ -particle)}\\v_2=?m/s$

Putting values in above equation, we get:

$238\times 1.895\times 10^5=4\times v_2\\\\v_2=\frac{238\times 1.895\times 10^5}{4}=1.127\times 10^7m/s$

Hence, the velocity of released alpha particle is $1.127\times 10^7m/s$

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3 years ago