Answer:


Explanation:
Given that:
The radius of the table r = 16 cm = 0.16 m
The angular velocity = 45 rpm
= 
= 4.71 rad/s
However, the relative velocity of the bug with turntable is:
v = 3.5 cm/s = 0.035 m/s
Thus, the time taken to reach the bug to the end is:


t = 4.571s
So the angle made by the radius r with the horizontal during the time the bug gets to the end is:



Now, the velocity components of the bug with respect to the table is:





Also, for the vertical component of the velocity 




Answer:
Ratio of series current to parallel
= 1 : 8
Explanation:
Total resistance Rt
For series, Rt = 2+2+2+2 = 4ohms
For parallel, 1/Rt = 1/2 + 1/2 + 1/2 + 1/2
1/Rt = 4/2, Rt = 2/4 ohms.
If we use a 1V battery, then,
I = V/Rt
I = 1/4 = 0.25 ampere for series arrangement.
I = 1/0.5 = 2 ohms.
Ratio of current of series to parallel = 0.25 : 2
= 1 : 8
Answer:
Honestly i think the answer is B
Explanation:
The force on the layer will be equivalent to the weight of water on it. This is given by:
F = mg; m is the mass of water and g is the acceleration due to gravity.