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3 years ago

Nh4i(aq)+koh(aq)→ express your answer as a chemical equation. identify all of the phases in your answer.

2 answers:

5 0

NH4I (aq) + KOH (aq) in chemical equation gives

NH4I (aq) + KOH (aq) = KI (aq) + H2O(l) + NH3 (l)

Ki is in aqueous state H2o is in liquid state while NH3 is in liquid state

from the equation above 1 mole of NH4I (aq) react with 1 mole of KOH(aq) to form 1mole of KI(aq) , 1mole of H2O(l) and 1 Mole of NH3(l)

Norma-Jean [14]3 years ago

4 0

Answer:

NH4I(aq) + KOH(aq) -------->KI(aq) + NH3(g) + H2O(l)

Explanation:

NH4I(aq) + KOH(aq) -------->KI(aq) + NH3(g) + H2O(l)

This is a reaction of aqueous ammonium iodide and aqueous potassium hydroxide to yield aqueous potassium iodide, gaseous ammonia and liquid water as shown above.

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Classify each of the following particulate level illustrations as a representation of either a pure substance, a homogeneous mix

Anarel [89]

Answer:

The classification and illustrations are attached in the drawing.

Explanation:

It is possible to identify the pure substance observing the figure, since it is the only one that has 2 joined atoms (purple and blue) which forms a single compound.

On the other hand, the homogeneous mixture is identified by noting that its atoms are more united with respect to the heterogeneous mixture, highlighting that in homogenous mixtures the atoms, elements or substances are not visible to the naked eye and are in a single phase, instead in the heterogeneous mixture if they can be differentiated.

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3 years ago

What is an intensive property? *

Dennis_Churaev [7]

Answer:A property that changes if the amount of substance changes

Explanation:

This is the answer

8 0

3 years ago

Does the amount of a substance affect the properties of a substance?

Veseljchak [2.6K]

No, the properties of a substance are not affected by the amount of a substance.

5 0

3 years ago

The combustion of ethene in the presence of excess oxygen yields carbon dioxide and water: c2h4 (g) + 3o2 (g) → 2co2 (g) + 2h2o

meriva

Answer:

$\boxed{-267.5}$

Explanation:

You can calculate the entropy change of a reaction by using the standard molar entropies of reactants and products.

The formula is

$\Delta_{r} S^{\circ} = \sum_n {nS_{\text{products}}^{\circ} - \sum_{m} {mS_{\text{reactants}}^{\circ}}}$

The equation for the reaction is

C₂H₄(g) + 3O₂(g) ⟶ 2CO₂(g) + 2H₂O(ℓ)

ΔS°/J·K⁻¹mol⁻¹ 219.5 205.0 213.6 69.9

$\Delta_{r} S^{\circ} = (2\times213.6 + 2\times69.9) - (1\times219.5 + 3\times205.0)\\\\= 567.0 - 834.5 = \boxed{-267.5 \text{ J}\cdot\text{K}^{-1} \text{mol}^{-1}}$

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3 years ago

To start the chemical reaction, what must happen between the enzyme and the substrate?.

yaroslaw [1]

The enzyme must attract substrates to its active state.
At the end of the reaction, products dissociate from the surface of the enzyme

6 0

2 years ago