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3 years ago

Nh4i(aq)+koh(aq)→ express your answer as a chemical equation. identify all of the phases in your answer.

2 answers:

5 0

NH4I (aq) + KOH (aq) in chemical equation gives

NH4I (aq) + KOH (aq) = KI (aq) + H2O(l) + NH3 (l)

Ki is in aqueous state H2o is in liquid state while NH3 is in liquid state

from the equation above 1 mole of NH4I (aq) react with 1 mole of KOH(aq) to form 1mole of KI(aq) , 1mole of H2O(l) and 1 Mole of NH3(l)

Norma-Jean [14]3 years ago

4 0

Answer:

NH4I(aq) + KOH(aq) -------->KI(aq) + NH3(g) + H2O(l)

Explanation:

NH4I(aq) + KOH(aq) -------->KI(aq) + NH3(g) + H2O(l)

This is a reaction of aqueous ammonium iodide and aqueous potassium hydroxide to yield aqueous potassium iodide, gaseous ammonia and liquid water as shown above.

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2.5 piece of lithium is dropped into a 500 g sample of water at 22.1 C.ten temperature of the water increases to 23.5 C. How muc

Dominik [7]

Answer:

2.6 kJ

Explanation:

The formula for the amount of heat (q) absorbed by the water is

q = mCΔT

1. Calculate ΔT

ΔT = 23.5 °C - 22.1 °C = 1.4 °C

2. Calculate q

q₂ = mCΔT = 500 g × 4.184 J·°C⁻¹g⁻¹ × 1.4 °C = 2900 J = 2.9 kJ

3 0

4 years ago

Lithium and nitrogen react in a combination reaction to produce lithium nitride: 6Li (s) + N2 (g) → 2Li3N (s) In a particular ex

seraphim [82]

Answer: 6.71 g

Explanation: $6Li(s)+N_2(g)\rightarrow 2Li_3N$

${\text{no of moles}}=\frac{\text{Given mass}}{\text{Molar mass}}$

${\text {moles of lithium}}=\frac{4g}{6.914g/mol}=0.578moles$

$\text{moles of nitrogen}=\frac{4g}{28g/mol}=0.143moles$

Limiting reagent is the reagent which limits the formation of product. Excess reagent is one which is in excess and thus remains unreacted.

Thus lithium is the limiting reagent and nitrogen is the excess reagent.

As can be seen from the balanced chemical equation, 6 moles of lithium reacts with 1 mole of nitrogen to give 2 moles of lithium nitride.

Thus 0.578 moles of lithium react with 0.096 moles of nitrogen.

6 moles of lithium give = 2 moles of lithium nitride

Thus 0.578 moles of lithium give= $\frac{2}{6}\times {0.578}=0.19moles$ of lithium nitride.

Mass of lithium nitride $Li_3N={\text {no of moles}}\times {\text {Molecular mass}}$

Mass of lithium nitride $Li_3N$ = ${0.192moles}\times {34.83g/mol}=6.71g$

8 0

3 years ago

Determine the heat needed to warm 25.3 g of copper from 22 degrees celsius to 39 degrees celsius.

Serggg [28]

Answer:

The heat needed to warm 25.3 g of copper from 22°C to 39°C is 165.59 Joules.

Explanation:

$Q=mc\Delta T$

Where:

Q = heat absorbed or heat lost

c = specific heat of substance

m = Mass of the substance

ΔT = change in temperature of the substance

We have mass of copper = m = 25.3 g

Specific heat of copper = c = 0.385 J/g°C

ΔT = 39°C - 22°C = 17°C

Heat absorbed by the copper :

$Q=25.3 g\times 0.385 J/g^oC\times 17^oC=165.59 J$

The heat needed to warm 25.3 g of copper from 22°C to 39°C is 165.59 Joules.

5 0

4 years ago

Which expression is a measurement of denisty

Ahat [919]

to calculate density you use the equation m/v. Divide the mass by the volume in order to get an object's density.

7 0

3 years ago

Give the formula of the conjugate base of each of the following. (Type your answer using the format CO2 for CO2, (NH4)2CO3 for (

MissTica

Answer:

a) [NH2]-,

b) [O]2-

c) [Cl]-

Explanation:

The conjugate base is the base member (X⁻) of a weak acid (HX). In other words, the conjugate base is the remaining substance due to the proton loss in the acid HX.

a) For NH₃, (HX; X: NH₂⁻), conjugate base is NH₂⁻. In the format, [NH2]-.

b) For OH⁻, (HX; X: O²⁻), conjugate base is O²⁻. In the format, [O]2-.

c) For HCl, (HX; X: Cl⁻), conjugate base is Cl⁻. In the format, [Cl]-.

7 0

3 years ago