We can solve for the resultant x and y components by using
the sine and cosine functions.
resultant x = 2.5 cos 35 + 5.2 cos 22 = 6.87 km
resultant y = 2.5 sin 35 + 5.2 sin 22 = 3.38 km
The resultant displacement is calculated using hypotenuse
equation:
displacement = sqrt (6.87^2 + 3.38^2)
displacement = 7.66 km
The resultant angle is:
θ = tan^-1 (3.38 / 6.87)
θ = 26.20°
Therefore the magnitude and direction is:
7.66 km, 26.20° to the ground
Answer:
<em>The sprinter traveled a distance of 7.5 m</em>
Explanation:
<u>Motion With Constant Acceleration
</u>
It's a type of motion in which the rate of change of the velocity of an object is constant.
The equation that rules the change of velocities is:
![v_f=v_o+at\qquad\qquad [1]](https://tex.z-dn.net/?f=v_f%3Dv_o%2Bat%5Cqquad%5Cqquad%20%5B1%5D)
Where:
a = acceleration
vo = initial speed
vf = final speed
t = time
The distance traveled by the object is given by:
![\displaystyle x=v_o.t+\frac{a.t^2}{2}\qquad\qquad [2]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x%3Dv_o.t%2B%5Cfrac%7Ba.t%5E2%7D%7B2%7D%5Cqquad%5Cqquad%20%5B2%5D)
Using the equation [1] we can solve for a:

The sprinter travels from rest (vo=0) to vf=7.5 m/s in t=2 s. Computing the acceleration:


Now calculate the distance:


The sprinter traveled a distance of 7.5 m
U=70 , v= 0, t=35, a=?
v=u+at
0=70+a(35)
-70=35a
a=-2m/s^2
Decelerate 2ms^-2 or acceleration is -2ms^-2
I\B
2/A
3\C
4\E
5\D
6\F
I think this is right