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Monica [59]
4 years ago
6

Cksjjsdkcjsdklxj ldjl ;xcjl 

Mathematics
1 answer:
MaRussiya [10]4 years ago
6 0
I like Turtles .. Do you ?
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Consider the plane, T, and three collinear points (but not coplanar) points P, Q, and W.
Montano1993 [528]

Answer:

vvv dvw

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5 0
3 years ago
How to solve 37=-3+5(x+6)
zavuch27 [327]
Distribute Property 5(x+6) basically means 5×x + 5×6 = 5x+30

37= -3+5x+30 (subtract 30 on both sides)

7=-3+5x (add three on both sides)

10= 5x (divide 5 on both sides)

x=2 
7 0
3 years ago
What is the value of x?<br> -2x = 8
STatiana [176]
This is a simply problem. Just divide both sides the coefficient of x. Which is -2.

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6 0
3 years ago
What is 2x - 1 &lt; 3? Solve
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Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
What is the standard form of the equation of a line for which the length of the normal segment to the origin is 8 and the normal
jeka57 [31]
Slope of line = tan(120) = -tan(60) = - &radic;3
Distance from origin = 8

Let equation be Ax+By+C=0
then -A/B=-&radic;3, or
B=A/&radic;3.
Equation becomes
Ax+(A/&radic;3)y+C=0

Knowing that line is 8 units from origin, apply distance formula
8=abs((Ax+(A/&radic;3)y+C)/sqrt(A^2+(A/&radic;3)^2))
Substitute coordinates of origin (x,y)=(0,0)  =>
8=abs(C/sqrt(A^2+A^2/3))
Let A=1 (or any other arbitrary finite value)
solve for positive solution of C
8=C/&radic;(4/3) => C=8*2/&radic;3 = (16/3)&radic;3

Therefore one solution is
x+(1/&radic;3)+(16/3)&radic;3=0
or equivalently
&radic;3 x + y + 16 = 0

Check:
slope = -1/&radic;3  .....ok
distance from origin
= (&radic;3 * 0 + 0 + 16)/(sqrt(&radic;3)^2+1^2)
=16/2
=8  ok.

Similarly C=-16 will satisfy the given conditions.

Answer  The required equations are
&radic;3 x + y = &pm; 16 
in standard form.

You can conveniently convert to point-slope form if you wish.




4 0
4 years ago
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