max is at vertex
in form 
the x value of the vertex is 
given, 
a=6, b=0
the x value of the vertex is -0/(2*6)=0
the y value is 
so vertex is at (0,-1)
since the value of a is positive, the parabola opens up and the vertex is a minimum value of the function
therefore that value is the smallest value the function can be
domain=numbesr you can use for x
range=numbesr you get out of inputting the domain
domain=all real numbers
range is {y | y≥-1} since y=-1 is the minimum
Answer:
z=40 degrees
Step-by-step explanation:
a triangle is 180 degrees
<ACB=50 (180-130=50)
50+90=140
180-140=40
523.6 m3 i hope this helps mark me as brainliest
Continuing from the setup in the question linked above (and using the same symbols/variables), we have
The next part of the question asks to maximize this result - our target function which we'll call
- subject to
.
We can see that
is quadratic in
, so let's complete the square.
Since
are non-negative, it stands to reason that the total product will be maximized if
vanishes because
is a parabola with its vertex (a maximum) at (5, 25). Setting
, it's clear that the maximum of
will then be attained when
are largest, so the largest flux will be attained at
, which gives a flux of 10,800.
A line passes through the points (p, a) and (p, –a) where p and a are real numbers. If p=0, what is the y-intercept? Explain your reasoning.
<span>p - as "x" never changes with the value of "y", so no matter what y is, x is always "p", so when y is 0, x = p </span>
<span>slope of the line </span>
<span>change in y over the change in x </span>
<span>(-a - a) / (p - p) = infinity - or a vertical line </span>
<span>equation of the line </span>
<span>y = p </span>
<span>slope of a line perpendicular to the given line </span>
<span>inverse of the orig slope or (p - p)/(-a - a) = 0</span>
