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givi [52]
3 years ago
11

The gravitational force between two objects has a magnitude of F. If both masses were doubled and the distance between them doub

led, the new force would have what magnitudes?
Physics
1 answer:
Fofino [41]3 years ago
7 0

Answer:

F' = F

Explanation:

The gravitational force of attraction between two objects can be given by Newton's Gravitational Law as follows:

F = \frac{Gm_1m_2}{r^2}

where,

F = Force of attraction

G = Universal gravitational costant

m₁ = mass of first object

m₂ = mass of second object

r = distance between objects

Now, if the masses and the distance between them is doubled:

F' = \frac{G(2m_1)(2m_2)}{(2r)^2}\\\\F' = \frac{Gm_1m_2}{r^2}

<u>F' = F</u>

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A circular wire loop has a radius of 7.50 cm. a sinusoidal electromagnetic plane wave traveling in air passes throughthe loop, w
ExtremeBDS [4]

Intensity of electromagnetic wave is given as

I = 2[\frac{B_{rms}^2}{2\mu_0}\times c]

given that

I = 0.0275 W/m^2

0.0275 = \frac{B_{rms}^2}{\mu_0} \times c

here we know that

\mu_0 = 4\pi \times 10^{-7}

c = 3 \times 10^8 m/s

now we have

0.0275 = \frac{B_{rms}^2}{4 \pi \times 10^{-7}}(3 \times 10^8)

B_{rms} = 1.07 \times 10^{-8} T

now we will have

B_0 = \sqrt2 B_{rms}

B_0 = 1.52 \times 10^{-8} T

frequency of wave is given as

f = \frac{c}{\lambda}

f = \frac{3 \times 10^8}{6.90} = 4.35 \times 10^7 Hz

now the induced EMF is given as

EMF = B_0A2\pi f

EMF = 1.52 \times 10^{-8} \times \pi(0.075)^2 \times (2\pi \times 4.25 \times 10^7)

EMF = 0.0733 Volts

7 0
3 years ago
Read 2 more answers
Find the weight of an object with mass 80 kg on the moon ( g = 1.6 m/s^2)
SpyIntel [72]

Answer:

80kg = 133 Newtons I'm pretty sure this is right.

5 0
2 years ago
Answer key says b but i think it is false please help me
klasskru [66]
Energy in a spring:

E = 0.5 * k * x²

k spring constant = 800 n/m
x stretch of the spring = 5 cm = 0.05 m

E = 0.5 * 800 * 0.05² = 1
5 0
3 years ago
Bill and amy want to ride their bikes to school which is 14.4 kilometers away. It takes Amy 49 minutes to get to school and bill
Drupady [299]

3.4m/s

Explanation:

Given parameters:

Distance to school  = 14.4km

Time taken by Amy = 49min

Time taken by bill = 20min after Amy = 20+49 = 69min

Unknown parameters:

How much faster is Amy's average speed = ?

Solution:

Average speed is the rate of change of total distance with total time taken.

 Average speed = \frac{total distance }{total time taken}

convert units to meters and seconds

      1000m = 1km

       60s = 1min

Distance to school  = 14.4 x 1000 = 14400m

Time taken by Amy = 49 x 60 = 2940s

Time taken by Bill = 69 x 60 = 4140s

Average speed of Amy = \frac{14400}{2940}  = 4.9m/s

Average speed of Bill = \frac{4140}{2940}  = 1.4m/s

Differences in speed = 4.9 - 1.5 = 3.4m/s

Amy was 3.4m/s faster than Bill

learn more:

Average speed brainly.com/question/8893949

#learnwithBrainly

5 0
3 years ago
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maksim [4K]

the above three pictures may help you

go through the attachments

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