<h2>
Answer:</h2>
-2324.4m/s²
<h2>
Explanation:</h2>
Use one of the equations of motion as follows;
v² = u² + 2as ------------------------(i)
Where;
v = final velocity of object
u = initial velocity of object
a = acceleration of the object
s = distance covered by the object
From the question, the object is the car and it has the following;
v = final velocity of the car = 0 (since it comes to a stop)
u = initial velocity of the car = 32km/h = (32 x 1000/3600) m/s = 8.89m/s
a = unknown
s = on a dime = 1.7cm = 0.017m
Substitute these values into equation (i) as follows;
=> 0² = 8.89² + (2 x a x 0.017)
=> 0 = 79.03 + (0.034a)
=> 0.034a = 0 - 79.03
=> 0.034a = - 79.03
=> a = - 
=> a = - 2324.4m/s²
Therefore, the acceleration of the car is -2324.4m/s².
Note that the negative sign indicates that the car is actually decelerating.
- deci: one-tenth.
- centi: one-hundredth.
- nano: one-billionth.
hope this helps :)
Answer:
Initial height L = 323.3m
Explanation:
Given:
Change in Length ∆L = 19.4cm 0.194m
Change in temperature ∆T = 41 -(-9) = 50°C
Coefficient of linear Thermal expansion of steel k = 12 × 10^-6 m/mK
Using the formula for linear expansion:
∆L = Lk∆T
L = ∆L/k∆T ....1
Substituting the given values into equation 1
L = 0.194/(12 × 10^-6 × 50)
Initial height L = 323.3m
Answer:
The pressure in a gas container is 839.44mmHg
Explanation:
Density of Mercury = 13.56g/cm³ = 13556kg/m³
hρg/ P₀
where, g= acceleration due to gravity, 10m/s²
h= height= 8.6cm = 0.086m
= hρg/ P₀
= 0.086 × 13556 × 10
= 11658.16 kgm/ m²s²
= 11658.16 N/m² = 11658.16pa
= 87.4434mmHg
where 1 torr = 1mmHg
= 752torr = 752mmHg
= 752 + 87.4434
= 839.44mmHg
Answer:
Dx = -0.5
Dy = -0.25
Explanation:
Two vectors are given in rectangular components form as follows:
A = i + 6j
B = 3i - 7j
It is also given that:
A - B - 4D = 0
so, we solve this to find D vector:
(i + 6j) - (3i - 7j) - 4D = 0
- 2i - j = 4D
D = - (2/4)i - (1/4)j
D = - (1/2)i - (1/4)j
<u>D = - 0.5i - 0.25j</u>
Therefore,
<u>Dx = -0.5</u>
<u>Dy = -0.25</u>
