Answer: There are few simple rules to follow.
(1) The atomic number is equal to the number of protons.
Z
= number of protons
(2) In neutrally charged elements, the number of electrons is the same as the number of protons.
Z
= number of protons = number of electrons (no charge)
Otherwise, positive charge means that the element lost an electron and negative charge means it gained an electron.
(3) The atomic mass is equal to the sum of the number of protons and number of neutrons.
A
= number of protons + number neutrons
or
A
=
Z
+ number neutrons
So if you say that
Z
= 20 and
A
= 40, then
A
=
Z
+ number neutrons
40 = 20 + number of neutrons
40 - 20 = number of neutrons
Therefore,
number of neutrons = 20
Explanation:
Answer:
B - (C , Al, P, Cl)
Explanation:
How I got this answer was by looking at my periodic table it shows you how much it contains by the Atomic number.
Atomic number on C (Carbon) is- 6
Atomic number on Al (Aluminum) is - 13
Atomic number on P (Phosphorus) is - 15
Atomic number on Cl (Chlorine) is - 17
Now it says least to greatest and the other options are wrong I did the work for you hope this helps :)) I also had this project you didnt ask but the answer for the The Lesson are {B E M S} which as the code numbers are gonna be -7494- Im glad to help if you need more help I will give you the other answers as well :) !
Answer:
V2= 0.0796m3
Explanation:
We have that for a real gas the following relation is fulfilled:
PV / T = constant
To use this formula I need to pass the pressure of mmHg to KPa and the volume of L to m3, knowing that
1Kpa = 7.50062mmHg
1L = 0.001m3
So i can say
P1V1/T1 =P2V2/T2
So
V2= P1V1T2/P2T1
V2= 51.60KPa*0.034m3*350k/36.53KPa*211k
finally
V2= 0.0796m3
The balanced equation for the above reaction is;
CH₄ + 2O₂ ---> CO₂ + 2H₂O
Stoichiometry of CH₄ to O₂ is 1:2
The number of methane moles present - 1.44 g/ 16 g/mol = 0.090 mol
Number of oxygen moles present - 9.5 g/ 32 g/mol = 0.30 mol
If methane is the limiting reagent,
0.090 moles of methane react with 0.090x 2 = 0.180 mol
only 0.180 mol of O₂ is required but 0.30 mol of O₂ has been provided therefore O₂ is in excess and CH₄ is the limiting reactant.
Number of moles of water that can be produced - 0.180 mol
Therefore mass of water produced - 0.180 x 18 g/mol = 3.24 g
Therefore mass of 3.24 g of water can be produced
