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zloy xaker [14]
3 years ago
5

What is dependent on the ability of water molecules to form hydrogen bonds with other molecules besides water

Chemistry
1 answer:
Vikentia [17]3 years ago
7 0

Answer:

The ability of water molecules to form hydrogen bonds with other molecules besides water is the universality of water as a solvent.

Explanation:

hope it helps you :)

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n200080 [17]
Potential energy or kinetic energy.
3 0
3 years ago
Complete the following equations : H3PO4 = 3H+ --------------- CaSO4 = Ca 2+ ---------------- (2) b) Write the formulae of the s
jeka94

Answer:

H₃PO₄ → 3H⁺ + PO₄³⁻

CaSO₄ → Ca²⁺ + SO₄²⁻

b. CaCl₂

Explanation:

When H₃PO₄ is dissolved in water, there are produced the H⁺ and PO₄³⁻ ions. The equation is:

H₃PO₄ → 3H⁺ + PO₄³⁻

In the same way, CaSO₄ is dissolved in:

CaSO₄ → Ca²⁺ + SO₄²⁻

b. Now, in a reaction of an acid (HCl) and a base (Ca(OH)₂), water, H₂O and a salt are produced:

2 HCl + Ca(OH)₂ → 2H₂O + Salt

The ions that are not present in the reaction are Cl⁻ and Ca²⁺, the salt is CaCl₂ and the balanced reaction is:

2 HCl + Ca(OH)₂ → 2H₂O + CaCl₂

5 0
3 years ago
The reaction is proceeding at a rate of 0.0080 Ms-1 in 50.0 mL of solution in a system with unknown concentrations of A and B. W
Leokris [45]

Answer:

0.0010 mol·L⁻¹s⁻¹  

Explanation:

Assume the rate law is  

rate = k[A][B]²

If you are comparing two rates,

\dfrac{\text{rate}_{2}}{\text{rate}_{1}} = \dfrac{k_{2}\text{[A]}_2[\text{B]}_{2}^{2}}{k_{1}\text{[A]}_1[\text{B]}_{1}^{2}}= \left (\dfrac{\text{[A]}_{2}}{\text{[A]}_{1}}\right ) \left (\dfrac{\text{[B]}_{2}}{\text{[B]}_{1}}\right )^{2}

You are cutting each concentration in half, so

\dfrac{\text{[A]}_{2}}{\text{[A]}_{1}} = \dfrac{1}{2}\text{ and }\dfrac{\text{[B]}_{2}}{\text{[B]}_{1}}= \dfrac{1}{2}

Then,

\dfrac{\text{rate}_{2}}{\text{rate}_{1}} = \left (\dfrac{1}{2}\right ) \left (\dfrac{1}{2}\right )^{2} = \dfrac{1}{2}\times\dfrac{1}{4} = \dfrac{1}{8}\\\\\text{rate}_{2} = \dfrac{1}{8}\times \text{rate}_{1}= \dfrac{1}{8}\times \text{0.0080 mol$\cdot$L$^{-1}$s$^{-1}$} = \textbf{0.0010 mol$\cdot$L$^{-1}$s$^{-1}$}\\\\\text{The new rate is $\large \boxed{\textbf{0.0010 mol$\cdot$L$^\mathbf{{-1}}$s$^{\mathbf{-1}}$}}$}

8 0
3 years ago
How do scientists think that gravity affected the formation of our solar system?
Makovka662 [10]
Maybe because gravity has control of each formation of the solarsydtem thats why its just a guess
5 0
3 years ago
R indicates round seeds that are dominant over the wrinkled variety represented by R for each numbered individual in the pedigre
hichkok12 [17]

Answer:

Explanation:X and Y

4 0
2 years ago
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