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Vaselesa [24]
2 years ago
5

The figure below is a regular octagon with a side length of 8 inches.

Mathematics
1 answer:
Masteriza [31]2 years ago
3 0

Answer:

309in²

Step-by-step explanation:

Area of an octagon is expressed as;

A=2(1+√2)a²

a is the side length of the octagon

Given

a = 8

Substitute into the formula

A = 2(1+√2)(8)²

A = 2(1+√2)(64)

Expand

A = 2(64+64√2)

A = 128+128√2

A = 128+128(1.414)

A = 128+181.01

A = 309in²

Hence the area of the octagon is 309in²

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Step-by-step explanation:

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(t1,v1) = (0,62817000) ----- In 2004

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Step-by-step explanation:

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Another math geometry question please help
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3 years ago
If 2(4x + 3)/(x - 3)(x + 7) = a/x - 3 + b/x + 7, find the values of a and b.
zmey [24]

Answer:

a=3 and b=5.

Step-by-step explanation:

So I believe the problem is this:

\frac{2(4x+3)}{x-3}(x+7)}=\frac{a}{x-3}+\frac{b}{x+7}

where we are asked to find values for a and b such that the equation holds for any x in the equation's domain.

So I'm actually going to get rid of any domain restrictions by multiplying both sides by (x-3)(x+7).

In other words this will clear the fractions.

\frac{2(4x+3)}{x-3}(x+7)}\cdot(x-3)(x+7)=\frac{a}{x-3}\cdot(x-3)(x+7)+\frac{b}{x+7}(x-3)(x+7)

2(4x+3)=a(x+7)+b(x-3)

As you can see there was some cancellation.

I'm going to plug in -7 for x because x+7 becomes 0 then.

2(4\cdot -7+3)=a(-7+7)+b(-7-3)

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-50=-10b

Divide both sides by -10:

\frac{-50}{-10}=b

5=b

Now we have:

2(4x+3)=a(x+7)+b(x-3) with b=5

I notice that x-3 is 0 when x=3. So I'm going to replace x with 3.

2(4\cdot 3+3)=a(3+7)+b(3-3)

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2(15)=10a+0

30=10a

Divide both sides by 10:

\frac{30}{10}=a

3=a

So a=3 and b=5.

4 0
3 years ago
Read 2 more answers
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