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olga55 [171]
3 years ago
5

What is the most fundamental property of a star in determining its evolution? luminosity temperature composition mass size?

Physics
1 answer:
Vitek1552 [10]3 years ago
5 0
The most fundamental property of a star that determines its evolution is the MASS of the star.

In fact, while low-mass stars usually end their life becoming red giants and then white or black dwarfs, the high-mass stars can evolve into red supergiants and eventually originate a supernova. After the explosion of the supernova, depending on their mass, they can becomes neutron stars or collapse into black holes.
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A plane flies from basecamp the Lake A, 280 km away in a direction of 20° north of
klasskru [66]

Answer:

308657

Explanation:

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3 years ago
Create a story of a “day in the life of a water drop”. Your story should be creative and include all 6 steps in the water cycle.
pogonyaev

Answer:

Explanation:

Ok so first: the evaporation part, the sun starts to get warmer I ( the water droplet) rises up to the sky to start my evaporation cycle

Condensation: part: when I am in the air I change into a gas and then I change back into a liquid and gather my friends and make a cloud

Precipitation: as it gets to crowded, we can’t hold it anymore, when I cool down I like to sky dive with my cousins, snow, rain, sleet, hail which is called precipitation.

Then finally we land on the ground, we run down hills, and run into lakes surface runoff happens when there’s too many of us so some of us can’t be rain. Infiltration: when some of us soak into the ground cause we can’t make it into the streams and oceans. Ok I can’t help much more cause I’m super busy but if you need more help just message me and I can help thx ! Hope I helped Atleast a bit for you to understand more

5 0
3 years ago
Read 2 more answers
By what factor would your weight be multiplied if the earth were1/2 as massavise and the diameter was unchanged
Nutka1998 [239]
<span>Let F be the force of gravity, G be the gravitational constant, M be the mass of the earth, m your mass and r the radius of the earth, then: 

F = G(Mm / (4(pi)*r^2)) 

The above expression gives the force that you feel on the earth's surface, as it is today! 

Let us now double the mass of the earth and decrease its diameter to half its original size. 

This is the same as replacing M with 2M and r with r/2. 

Now the gravitational force (F' ) on the new earth's surface is given by: 

F' = G(2Mm / (4(pi)(r/2)^2)) = 2G(Mm / ((1/4)*4(pi)*r^2)) = 8G(Mm / (4(pi)*r^2)) = 8F 

So: 

F' = 8F 

This implies that the force that you would feel pulling you down (your weight) would increase by 800%! 

You would be 8 times heavier on this "new" earth!</span>
4 0
3 years ago
Give two environmental effects of using wood as an energy resource.
vladimir2022 [97]

Answer:

Using wood also helps keep carbon out of the atmosphere, helping to mitigate climate change.

Deforestation.  

Explanation:

Trees store carbon dioxide as they grow. After harvest, wood products continue to store much of this carbon. These benefits continue when wood is reclaimed to manufacture other products.

Extraction of wood within the supply areas clearly affects the forest and the environment. Some of these impacts can be seen in the study areas. The rainfall is increasingly irregular, biodiversity has been lost. Communities have experienced flooding and drought, which adversely affects the most important sector in the country's economy, that of agriculture. The local populations are concerned about these impacts, which affect not only the environment but the whole social economy.

6 0
2 years ago
Read 2 more answers
An atom of carbon has a radius of 67.0 pm and the average orbital speed of the electrons in it is about 1.3 x 10⁶ m/s.
adoni [48]

Answer :

The least possible uncertainty in an electron's velocity is, 4.32\times 10^{5}m/s

The percentage of the average speed is, 33 %

Explanation :

According to the Heisenberg's uncertainty principle,

\Delta x\times \Delta p=\frac{h}{4\pi} ...........(1)

where,

\Delta x = uncertainty in position

\Delta p = uncertainty in momentum

h = Planck's constant

And as we know that the momentum is the product of mass and velocity of an object.

p=m\times v

or,

\Delta p=m\times \Delta v      .......(2)

Equating 1 and 2, we get:

\Delta x\times m\times \Delta v=\frac{h}{4\pi}

\Delta v=\frac{h}{4\pi \Delta x\times m}

Given:

m = mass of electron = 9.11\times 10^{-31}kg

h = Planck's constant = 6.626\times 10^{-34}Js

radius of atom = 67.0pm=67.0\times 10^{-12}m     (1pm=10^{-12}m)

\Delta x = diameter of atom = 2\times 67.0\times 10^{-12}m=134.0\times 10^{-12}m

Now put all the given values in the above formula, we get:

\Delta v=\frac{6.626\times 10^{-34}Js}{4\times 3.14\times (134.0\times 10^{-12}m)\times (9.11\times 10^{-31}kg)}

\Delta v=4.32\times 10^{5}m/s

The minimum uncertainty in an electron's velocity is, 4.32\times 10^{5}m/s

Now we have to calculate the percentage of the average speed.

Percentage of average speed = \frac{\text{Uncertainty in speed}}{\text{Average speed}}\times 100

Uncertainty in speed = 4.32\times 10^{5}m/s

Average speed = 1.3\times 10^{6}m/s

Percentage of average speed = \frac{4.32\times 10^{5}m/s}{1.3\times 10^{6}m/s}\times 100

Percentage of average speed = 33.2 % ≈ 33 %

Thus, the percentage of the average speed is, 33 %

3 0
3 years ago
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