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Pavel [41]
3 years ago
11

How is the atomic mass of an atom determined?​

Physics
1 answer:
Ipatiy [6.2K]3 years ago
5 0

Answer:

Atomic mass is defined as the number of protons and neutrons in an atom

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Atomic theory describes the motion of particles in solids, liquids, and gases. Which statement best describes the particles in a
Alex787 [66]
B is the answer because a solid would not be able to hold its shape if it was able to move around
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3 years ago
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In your research lab, a very thin, flat piece of glass with refractive index 1.20 and uniform thickness covers the opening of a
liraira [26]

Answer:

(a). The thickness of the glass is 868 nm.

(b). The wavelength is 3472 nm.

Explanation:

Given that,

Refractive index = 1.20

Wavelength = 496 nm

Next wavelength = 386 nm

We need to calculate the thickness of the glass

Using formula for constructive interference

2nt=(m+\dfrac{1}{2})\lambda

Put the value into the formula

In first case,

2nt=(m+\dfrac{1}{2})496.....(I)

In second case,

2nt=(m+1+\dfrac{1}{2})386

2nt=(m+\dfrac{3}{2})386.....(II)

From equation (I) and (II)

(m+\dfrac{1}{2})496=(m+\dfrac{3}{2})386

110m=336

m=3.0

Put the value of m in equation (I)

2nt=(2+\dfrac{1}{2})496

t=\dfrac{(3+\dfrac{1}{2})496}{2\times1}

t=868\ nm

The thickness of the glass is 868 nm.

(b). We need to calculate the wavelength

Using formula of constructive interference

2nt=(m+\dfrac{1}{2})\lambda

\lambda=\dfrac{2nt}{(m+\dfrac{1}{2})}

Put the value into the formula

\lambda=\dfrac{2\times1\times868}{\dfrac{1}{2}}

\lambda=3472\ nm

Hence, (a). The thickness of the glass is 868 nm.

(b). The wavelength is 3472 nm.

8 0
4 years ago
Is that possible to separate the water particles from the air
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3 years ago
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Since most people who are electrocuted don’t blow up, what kills them?
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8 0
4 years ago
Use Wien’s Law to calculate the peak wavelength of Betelgeuse, based on the temperature found in Question #8. Note: 1 nanometer
kodGreya [7K]

The peak wavelength of Betelgeuse is 828 nm

Explanation:

The relationship between surface temperature and peak wavelength of a star is given by Wien's displacement law:

\lambda=\frac{b}{T}

where

\lambda is the peak wavelength

T is the surface temperature

b=2.898\cdot 10^{-3} m\cdot K is Wien's constant

For Betelgeuse, the surface temperature is approximately

T = 3500 K

Therefore, its peak wavelength is:

\lambda=\frac{2.898\cdot 10^{-3}}{3500}=8.28\cdot 10^{-7} m = 828 nm

Learn more about wavelength:

brainly.com/question/5354733

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#LearnwithBrainly

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