Ask question

Ask question

All categories

3 years ago

7

five friends bought admission tickets to the museum and a box lunch. The cost of each admission ticket was 11.75$. Each box lunc

h was 5$. Write two equivalent expressions and then find the total cost.

2 answers:

Anna71 [15]3 years ago

5 0

Yeah it’s 83.75$ .......

IrinaK [193]3 years ago

4 0

Answer:

83.75$

Step-by-step explanation:

(5×11.75)+5×(5)=?

5×(11.75+5)=? [DISTRIBUTIVE PROPERTY]

5×16.75=?

83.75

You might be interested in

What is 5+5+5+5+5+5+5+5+5+5+5+5+5

professor190 [17]

Answer:

65

Step-by-step explanation:

13x5 = 65

4 0

3 years ago

Read 2 more answers

Y + 2 = -3(x - 4). What is the slope?

VARVARA [1.3K]

Answer:

m=-3

Step-by-step explanation:

6 0

3 years ago

Find the P-value in a test of the claim that the mean IQ score of acupuncturists is equal to 100, given that the test statisti

klemol [59]

Answer:

P-value = 0.0455

Step-by-step explanation:

In this question, we are concerned with calculating the P- value in a test.

Mathematically we know that;

P-value = 2 * P(Z > |z|)

Please check attachment for complete solution and by step explanation

7 0

3 years ago

The measure of <1<br> A 60<br> B 120<br> C 240

Georgia [21]

The measurement of angle 1 is 60

8 0

3 years ago

Which expression is equivalent to StartFraction (5 a b) cubed Over 30 a Superscript negative 6 Baseline b Superscript negative 7

m_a_m_a [10]

Answer:

Option D.

Step-by-step explanation:

The given expression is

$\dfrac{(5ab)^3}{30a^{-6}b^{-7}}$

We need to find the expression, which is equivalent to the given expression.

The given expression can be rewritten as

$\dfrac{5^3a^3b^3}{30a^{-6}b^{-7}}$ $[\because (ab)^m=a^mb^m]$

$\dfrac{125}{30}\times \dfrac{a^3}{a^{-6}}\times \dfrac{b^3}{b^{-7}}$

$\dfrac{25}{6}\times a^{3-(-6)}\times b^{3-(-7)}$ $[\because \dfrac{a^m}{a^n}=a^{m-n}]$

$\dfrac{25}{6}\times a^{3+6}\times b^{3+7}$

$\dfrac{25a^9b^{10}}{6}$

Therefore, the correct option is D.

7 0

3 years ago