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Finger [1]
3 years ago
7

five friends bought admission tickets to the museum and a box lunch. The cost of each admission ticket was 11.75$. Each box lunc

h was 5$. Write two equivalent expressions and then find the total cost.​
Mathematics
2 answers:
Anna71 [15]3 years ago
5 0
Yeah it’s 83.75$ .......
IrinaK [193]3 years ago
4 0

Answer:

83.75$

Step-by-step explanation:

(5×11.75)+5×(5)=?

5×(11.75+5)=? [DISTRIBUTIVE PROPERTY]

5×16.75=?

83.75

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Elementary math! please help Mark brainlist​
algol [13]

Answer: 1 minute and 43 seconds faster

Step-by-step explanation:

4 0
3 years ago
adiocarbon dating of blackened grains from the site of ancient Jericho provides a date of 1315 BC ± 13 years for the fall of the
Zigmanuir [339]

Answer:

\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659 and \left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661

Step-by-step explanation:

The equation of the isotope decay is:

\frac{m(t)}{m_{o}} = e^{-\frac{t}{\tau} }

14-Carbon has a half-life of 5568 years, the time constant of the isotope is:

\tau = \frac{5568\,years}{\ln 2}

\tau \approx 8032.926\,years

The decay time is:

t = 1315\,years + 2007\,years \pm 13\,years (There is no a year 0 in chronology).

t = 3335 \pm 13\,years

Lastly, the relative amount is estimated by direct substitution:

\frac{m(t)}{m_{o}} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\mp\frac{13\,years}{8032.926\,years} }

\left(\frac{m(t)}{m_{o}} \right)_{min} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{-\frac{13\,years}{8032.926\,years} }

\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659

\left(\frac{m(t)}{m_{o}} \right)_{max} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\frac{13\,years}{8032.926\,years} }

\left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661

4 0
3 years ago
Guerby ran 10 miles in 2 hrs, how many miles did he run in 1hr?
Strike441 [17]

Answer:

5 not including rests and what speed.

Step-by-step explanation:

plz mark me brainlyiist :)

8 0
3 years ago
The lengths, in minutes, of the movies currently showing at a movie theater are shown in the data set. ​ ​ ​ ​Create a histogram
alexdok [17]

Answer:

See Explanation

Step-by-step explanation:

The question is incomplete, as the required lengths are not given.

I will use the following data set to answer the question.

Dataset: 35, 51, 39, 42, 68, 62, 32, 59

First, is to determine the range of the dataset

Range = Highest - Least

Range = 68 - 32

Range = 36

Next, we will make use of 4 classes. So, we divide range by 10 to get the number of class. 10 represents the interval

Class= Range/10

Class = 36/10

Class = 3.6

Class \approx 4

<em>So, we use 4 classes</em>

Plot the frequency distribution table as follows:

\begin{array}{ccc}{Intervals} & {Observations} & {Frequency} & {31-40} & {32,35,39} & {3} & {41-50} & {42} & {1} & {51-60} & {51,59} & {2} & {61-70} & {62,68} & {2}\ \end{array}

<em>See attachment for histogram</em>

5 0
3 years ago
Please help me with this question please
lora16 [44]

Answer:

○ sin 15° = sin 30°⁄2 = ±√[1 - cos 30°\2]

Step-by-step explanation:

According to the Sine Half-Angle Identity, this is the formula:

sin x = sin ˣ⁄2 = ±√[1 - cos x\2]

Notice the <em>-</em><em>cos</em><em> </em><em>x</em><em>\</em><em>2</em><em> </em>inside the radical. The second option nearly resembles this option. It has a positive symbol inside. Do not let this confuse you. The Cosine Half-Angle Identity is the formula that has a positive in the radical:

cos x = cos ˣ⁄2 = ±√[1 + cos 30°\2]

I am joyous to assist you anytime.

7 0
3 years ago
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