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Neporo4naja [7]
3 years ago
15

When a light ray is reflected from a surface, the ratio of the angle of incidence to the angle of reflection is

Physics
1 answer:
balandron [24]3 years ago
7 0

Answer:

equal to 1

Explanation:

When any ray of light falls or strikes on a surface, the ray is reflected back and the angle of reflection is equal to angle of the incidence, where both the angles are always measured from the path of light that is normal to surface of the point at which the ray of light strikes the surface. This is called as the laws of reflection of light.

And therefore, the ratio of the angle of incidence to the angle of reflection is always equal to 1.

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40 meters divided by 5
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8 meters

Explanation:

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The cells in your body help get oxygen to cellular respiration. 
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A stone dropped from the top of a building reaches the ground with a velocity of 49ms¹. If the acceleration due to gravity is 9.
bezimeni [28]

Explanation:

Given:

v₀ = 0 m/s

v = 49 m/s

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6 0
2 years ago
A spherical asteroid of average density would have a mass of 8.7×1013kg if its radius were 2.0 km.A)If you and your spacesuit ha
WITCHER [35]

A) 0.189 N

The weight of the person on the asteroid is equal to the gravitational force exerted by the asteroid on the person, at a location on the surface of the asteroid:

F=\frac{GMm}{R^2}

where

G is the gravitational constant

8.7×10^13 kg is the mass of the asteroid

m = 130 kg is the mass of the man

R = 2.0 km = 2000 m is the radius of the asteroid

Substituting into the equation, we find

F=\frac{(6.67\cdot 10^{-11})(8.7\cdot 10^{13} kg)(130 kg)}{(2000 m)^2}0.189 N=

B) 2.41 m/s

In order to orbit just above the surface of the asteroid (r=R), the centripetal force that keeps the astronaut in orbit must be equal to the gravitational force acting on the astronaut:

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where

v is the speed of the astronaut

Solving the formula for v, we find the minimum speed at which the astronaut should launch himself and then orbit the asteroid just above the surface:

v=\sqrt{\frac{2GM}{R}}=\sqrt{\frac{2(6.67\cdot 10^{-11})(8.7\cdot 10^{13} kg)}{2000 m}}=2.41 m/s

3 0
3 years ago
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