Lithium 7 has an equal number of protons and neutrons.
NH₃ + H₂O ⇄ NH₄⁺ + OH⁻
c=9,50*10⁻² mol/L
Ammonia solution is a weak electrolyte.
The dissociation constant of ammonium hydroxide is:
K=1.78*10⁻⁵
[OH⁻]=√(Kc)
pH=14-pOH=14+lg[OH]⁻
pH=14+lg(√(Kc))
pH=14+lg(√(1.78*10⁻⁵*9.50*10⁻²))=8.23
pH=8.23
11 with pemdas, you have to multiply all by 3
I believe it is 56.3 hope this helps
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