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LenaWriter [7]
2 years ago
13

What is the volume of the cube shown? 1/4 cm

Mathematics
1 answer:
murzikaleks [220]2 years ago
7 0

(1/64)cm^3

Step-by-step explanation:

edge(a)= 1/4cm

volume of cube

=a^3

=(1/4)^3

=(1/64)cm^3

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Math! 30 points + brainliest
Ronch [10]

Answer:

A) 9.56x10^38 ergs

B) 7.4x10^-3 mm

Step-by-step explanation:

A) 9.56x10^38 ergs B) 7.4x10^-3 mm A). For the sun, just multiply the power by time, so 3.9x10^33 erg/sec * 2.45x10^5 sec = 9.56x10^38 B) Of the two values 7.4x10^-3 and 7.4x10^3, the value 7.4x10^-3 is far more reasonable as a measurement for blood cell. Reason becomes quite evident if you take the 7.4x10^3 value and convert to a non-scientific notation value. Since the exponent is positive, shift the decimal point to the right. So 7.4x10^3 mm = 7400 mm, or in easier to understand terms, over 7 meters. That is way too large for a blood cell when you consider that you need a microscope to see one. Now the 7.4x10^-3 mm value converts to 0.0074 mm which is quite small and would a reasonable size for a blood cell.



6 0
3 years ago
Read 2 more answers
Ms.jan brought in cookies for her class.She gave out half of them in the morning. At lunch,she gave out 12 more.She then had 1o
Nikolay [14]

Answer:

So we know that Ms. Jan had brought the class cookies and gave out half of them the cookies she had in all was 34 she then gave the class 12 in the morning and 22 cookies was left then at lunch it she gave out 12 more so 22-12 is 10

Step-by-step explanation:

34 cookies -12=22 cookies-12=10 cookies left.

I HOPE THIS HELPS :)

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1 year ago
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Find the solution set for this equation. Separate the two values with a comma.
adelina 88 [10]
Y^2 -11y = 0

We can factor it:
y * (y -11) = 0

So y = 11, 0


3 0
3 years ago
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A baseball is thrown in a parabolic arc. It's position above the ground at a given point in time can be represented by the quadr
SCORPION-xisa [38]

Answer:

The baseball reached 9 feet high above the ground

Step-by-step explanation:

The given quadratic function representing the position of the baseball above ground is p(t) = 1/2·g·t² + v₀·t + p₀

Where;

t ≥ 0

g = -32 ft./sec²

v₀ = The initial velocity

p₀ = The initial position

Given that when the ball is thrown, we have;

The initial, straight up, velocity, v₀ = 16 ft./sec

The initial position, p₀ = 5 ft.

Substituting the above values in the quadratic function representing the position of the baseball above ground, we have;

p(t) = 1/2·(-32)·t² + 16·t + 5 = 16·t - 16·t² + 5

At the maximum point, the rate of change of the height with time = 0, therefore;

dp(t)/dt = 0 = d(16·t - 16·t² + 5)/dt = 16 - 32·t

16 - 32·t = 0

16 = 32·t

t = 16/32 = 0.5 seconds

Therefore, the time takes to reach the maximum height = 0.5 seconds

The height (maximum) reached in 0.5 seconds is given as follows;

h(t) = 16·t - 16·t² + 5, from which we have;

h(0.5) = 16 × 0.5 - 16 × (0.5)² + 5 = 9

Therefore, the height baseball reached = 9 ft. above ground

7 0
2 years ago
Domain and range please? Graph
Kamila [148]
The domain is {-1.5, -1.2, -0.8, -0.5, 0, 1, 2} And the range is {0, -3}
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2 years ago
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