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3 years ago

Is this graph a function? why or why not.

Mathematics

2 answers:

Amanda [17]3 years ago

4 0

Answer:

Step-by-step explanation:

Reil [10]3 years ago

3 0

Answer:

The vertical line test can be used to determine whether a graph represents a function. ... If we can draw any vertical line that intersects a graph more than once, then the graph does not define a function because that x value has more than one output. A function has only one output value for each input value.

Step-by-step explanation:

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Sinx + siny=a<br> cosx + cosy=b<br> Find cos(x+y/2)

romanna [79]

Using the addition rule of the Sine function and the Cosine function, we obtain $\cos\dfrac{x+y}{2}=\dfrac{b}{\sqrt{a^2+b^2}}$ .

<h3>What are the formulas for (sin x + sin y) and (cos x + cos y)?</h3>

The formula for the addition of two Sine functions ( $\sin x+\sin y$ ) is $\sin x + \sin y = 2\sin\frac{x+y}{2}\cos\frac{x-y}{2}$ .
The formula for the addition of two Cosine functions ( $\cos x+\cos y$ ) is $\cos x + \cos y = 2\cos\frac{x+y}{2}\cos\frac{x-y}{2}$ .

Given that

$\sin x + \sin y = a\\\cos x + \cos y = b$

Then using the above formulas, we get:

$2\sin\frac{x+y}{2}\cos\frac{x-y}{2}=a$ (1)

$2\cos\frac{x+y}{2}\cos\frac{x-y}{2}=b$ (2)

Dividing the equation (1) by (2), we get:

$\dfrac{\sin\dfrac{x+y}{2}}{\cos\frac{x-y}{2}}=\dfrac{a}{b}\\\Longrightarrow \tan\dfrac{x+y}{2}=\dfrac{a}{b}$ (3)

Now, we know that $\cos\theta=\dfrac{1}{\sqrt{1+\tan^2\theta}}$ .

Thus, using the above formula, we get from (3):

$\cos\dfrac{x+y}{2}=\dfrac{1}{\sqrt{1+\tan^2\dfrac{x+y}{2}}}\\\Longrightarrow \cos\dfrac{x+y}{2}=\dfrac{1}{\sqrt{1+\dfrac{a^2}{b^2}}}\\\Longrightarrow \cos\dfrac{x+y}{2}=\dfrac{b}{\sqrt{a^2+b^2}}$

Therefore, using the addition rule of the Sine function and the Cosine function, we obtain $\cos\dfrac{x+y}{2}=\dfrac{b}{\sqrt{a^2+b^2}}$ .

To know more about Sine and Cosine functions, refer: brainly.com/question/27728553

#SPJ9

3 0

2 years ago

57 ÷ (9 + 3) – 8<br> who knows the anwser

vitfil [10]

Answer in decimal form: -3.25
answer in improper fraction form: - 13/4
answer in fraction form: -3 1/4

Hope this helped!

6 0

2 years ago

What is the solution to the system of equations

vitfil [10]

Answer:

Step-by-step explanation:

Hello

I believe there is an error in the question

we have two equations and need to find x and y

$(1) \dfrac{1}{4}x+\dfrac{1}{2}y=\dfrac{5}{8}\\(2) \dfrac{3}{4}x-\dfrac{1}{2}y=3\dfrac{3}{8}$

let s multiply by 8 so that we can get rid of the fractions

(1) becomes 2x+4y=5

(2) becomse 6x-4y=9

if we sum it gives

2x+4y+6x-4y=9+5

8x=14

x = 14/8 = 7/4

and then from the first equation

4y = 5 - 7/4

<=> 16y = 20-7 = 13

y = 13/16

the solutions is (7/4,13/16)

5 0

3 years ago

5. If a rectangle has a perimeter of 10 feet and is 2 feet wide what's the area?

Fudgin [204]

Answer:

Step-by-step explanation:

What you would do is multiply 10 and 2 and get 20

Please mark me brainliest

5 0

3 years ago

The ratio of adults to children is 8:5 of 390 people

Misha Larkins [42]

This ratio can be written as 8x+5x =390 Add the variables 13x = 390 Divide by 13 to get the value of x 390/13 = 30

6 0

3 years ago

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