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DiKsa [7]
2 years ago
7

QUESTION 4.

Physics
1 answer:
n200080 [17]2 years ago
8 0

Answer:

Follows are the solution to this question:

Explanation:

Please find the correct question in the attachment file.

Let:

\overrightarrow{R}= R_i\hat{i}+R_j\hat{j}+R_k\hat{k}\\\\\overrightarrow{S}= S_i\hat{i}+S_j\hat{j}+S_k\hat{k}\\\\

Calculating the value of  \overrightarrow{R} \times \overrightarrow{S}:

\to \left | \begin{array}{ccc}\hat{i}&\hat{j}&\hat{K}\\R_i&R_j&R_k\\S_i&S_j&S_k\end{array}\right | = \hat{i}[R_j S_k-S_jR_k]-\hat{j}[R_i S_k-S_iR_k]+\hat{k}[R_i S_j-S_iR_j]

Calculating the value of \overrightarrow{R}  \cdot (\overrightarrow{R} \times \overrightarrow{S}):

\to (R_i\hat{i}+R_j\hat{j}+R_k\hat{k}) \cdot ( \hat{i}[R_j S_k-S_jR_k]-\hat{j}[R_i S_k-S_iR_k]+\hat{k}[R_i S_j-S_iR_j])

by solving this value it is equal to 0.

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At the beginning of 2016, robotics inc. acquired a manufacturing facility for $13.1 million. $10.1 million of the purchase price
ki77a [65]

$ 376153 is depreciation on the building for 2018.

<u>Explanation:</u>

Given data:

Original cost = $13.1 million

Residual value = $2.1 million

Useful life = 20 -year  

Depreciation on the building for 2016 = =\frac{\text {original cost-residual value}}{\text { Useful life }}

By substituting the given values, we get,

        =\frac{(\$ 13.1 \text { million }-\$ 2.1\text { million) } }{20 \text { years }}=\frac{11.1 \text { million }}{20 \text { years }} = 5500000

Depreciation for 2016 $5500000

Depreciation for 2017 $5500000

Depreciation at Dec 31, 2017 $ 5500000

In 2018, the estimates of useful life and residual value were changed to 15 years and $610000, but 2 yrs have already passed, so there're 13 more yrs to go.

Depreciation on the building for 2018,

      =\frac{\text { book value at the end of } 2016-\text {residual value}}{\text { useful life }}

        = =\frac{\$ 5500000-\$ 610000}{13}=\frac{4890000}{13}=\$ 376153

4 0
3 years ago
PLEASE HELP<br> The image characteristics are...
VLD [36.1K]

According to the question, the object is placed at 2F

The ray diagram is shown in the figure attached.

According to the figure:

Object AB is at 2F₁

First, we draw a ray parallel to principal axis.

So, it passes through focus after refraction.

We draw another ray which passes through optical center.

So, the ray will go through without any deviation.

Where both refracted rays meet is point A' and the image formed is A'B'

This image is formed at 2F₂

We can say that:

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Which letter on the map represents Australia?
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C because it literally in Australia but the pfp tho

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A hypothetical planet has a mass 2.81 times that of Earth, but the same radius.
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The acceleration due to gravity near the surface of the planet is 27.38 m/s².

<h3>Acceleration due to gravity near the surface of the planet</h3>

g = GM/R²

where;

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g = (6.626 x 10⁻¹¹ x 2.81 x 5.97 x 10²⁴) / (6371 x 10³)²

g = 27.38 m/s²

Thus, the acceleration due to gravity near the surface of the planet is 27.38 m/s².

Learn more about acceleration due to gravity here: brainly.com/question/88039

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