A) 1 rev = 2π rad. Using this ratio, you can find the rad/s: 1160 rev/min x 2π rad/rev x 1 min/60 s = 121.5 rad/s
b) You can find linear speed from angular speed using this equation (note the radius is half the diameter given in the question): v = ωr = 121.5 rad/s x 1.175 m = 142.8 m/s
c) You can find centripetal acceleration using this equation: a = v^2/r = (142.8 m/s)^2 / 1.175 m = 17 355 m/s^2
Answer:
6.1328 kg
60.16284 N
Explanation:
r = Radius of ball = 0.11 m
= Density of fluid = (Assumed)
g = Acceleration due to gravity = 9.81 m/s²
m = Mass of ball
V = Volume of ball =
The weight of the bowling ball will balance the buouyant force
The mass of the bowling ball will be 6.1328 kg
Weight will be
Answer:
Explanation:
a ) A force of 6 N , causes elongation of .03 m
Spring constant
k = 6 / .03
= 200 N / m
b )
Amplitude A = .04 m .
Maximum velocity of a particle in SHM
= ωA where ω is angular velocity and A is amplitude
= x A
= x A
= 20x .04 = 0.8
Maximum velocity of a particle
= 0.8 m ² s
Minimum velocity will be zero at extreme point ( at turning point )
c )
Minimum acceleration is zero at middle point ( equilibrium position )
maximum acceleration
= ω²A
= k / m x A
= 400 x .04
= 16 m / s
d )
At halfway point velocity will be √ 3 / 2 times the maximum velocity
velocity at mid point
= √ 3 / 2 x max velocity
.866 x
= .866 x 0.8
= .693 m /s
Ive passed several physics classes. What's your question?