If the boat's velocity is 18m/sec relative to the water in the river and not the shore, it would need to be added the river speed of 2.5m/sec to get a total of 20.5m/sec. The 20.5m/sec would then be the total velocity of the boat relative to the shore. From personal experience, I know that when one runs with the tide, one is adding the tide flow speed to one's boat speed (what it would be in neutral waters) to get a sometimes much faster speed.
Resistance can be obtained by the following formula:
R = <span>ρ (L/A)
where:
R = resistance
</span>ρ = resistivity of copper (<span>1.68<span>x10^-8</span></span>)
L = Length = 3.1m
A = cross-sectional area = pi * (d/2)^2 = pi * (1.7mm)^2 = 2.269 mm^2
R = (1.68x10^-8) (3.1 / 0.0000022698)
R = 0.0229 <span>Ω</span>
It's actually B - The 6 kg ball has a greater force of gravity exerted on them
Answer;
velocity(v) = 97.2 m/s ,
distance (S) = 100 m
determine time(t) = ?
We know that,
distance (S) = velocity(v) × time(t)
So, time (t) = distance ÷ velocity
= 100 ÷ 97.2
<em> t = 1.02 sec.</em>
<em>I hope this will help you.</em>
The most accurate answer among the choices would be the fourth one, because if the weight of the air displaced is greater than the balloon's weight, the balloon will float upwards. Density of the air also plays a part. Hot air = less dense. Hope my answer has come to your help.
