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LiRa [457]
2 years ago
7

How has the study of fossil rocks evolved over time? (personal answer)

Chemistry
1 answer:
d1i1m1o1n [39]2 years ago
3 0

Answer:

When an organism dies, it is usually destroyed by other forms of life and by weathering processes. On rare occasions some body parts—particularly hard ones such as shells, teeth, or bones—are preserved by being buried in mud or protected in some other way from predators and weather. Eventually, they may become petrified and preserved indefinitely with the rocks in which they are embedded. Methods such as radiometric dating—measuring the amounts of natural radioactive atoms that remain in certain minerals to determine the elapsed time since they were constituted—make it possible to estimate the time period when the rocks, and the fossils associated with them.

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There are 3 different possible structures (known as isomers) for a dibromoethene molecule, C2H2Br2. One of them has no net dipol
nevsk [136]

Explanation:

Compounds having same molecular formula but different structural and spatial arrangement are isomers.

Three isomers are possible for dibromomethene.

In one structure (IUPAC name: 1,1-dibromomethene), both the bromine atoms are attached to one carbon atom.

In another two structures (Cis and trans), two bromine atoms are attached to two different carbon atoms.

In Cis 1,2-dibromomethene, two bromine atoms are present on the same side.

Whereas in Cis 1,2-dibromomethene, two bromine atoms are present on the opposite side and hence, does not have net dipole moment.

5 0
3 years ago
Giải gấp giúp em câu này với ạ:
padilas [110]

Explanation:

what do you have written I can't understand one word right a properly

6 0
3 years ago
How much Naclo3 will dissolve at 50°C?
Shkiper50 [21]

Answer:

90.  

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5 0
2 years ago
What mass of precipitate forms when 185.5 ml of 0.533 m naoh is added to 627 ml of a solution that contains 15.8 g of aluminum s
Law Incorporation [45]

Answer:

2,57 g of precipitate.

Explanation:

For the reaction:

6 NaOH + Al₂(SO₄)₃ → 2 Al(OH)₃ + 3 Na₂SO₄

The precipitate is Al(OH)₃.

185,5mL of 0,533M NaOH are:

0,1855L × 0,533M = <em>0,0989 moles NaOH</em>

Moles of Al₂(SO₄)₃ are:

15,8g × \frac{1mol}{342,15g} = <em>0,0462 moles Al₂(SO₄)₃</em>

For the total reaction of 0,0989 moles NaOH with Al₂(SO₄)₃ you need:

0,0989moles NaOH × \frac{1molAl_{2}(SO_{4})_{3}}{6 moles NaOH} = <em>0,0165 moles Al₂(SO₄)₃</em>

As you have <em>0,0462 moles Al₂(SO₄)₃ </em>the limiting reactant is NaOH.

0,0989 moles of NaOH produce:

0,0989moles NaOH × \frac{2molAl(OH)_{3}}{6 moles NaOH} = <em>0,0330 moles of Al(OH)₃</em>

These moles are:

0,0330 moles of Al(OH)₃ × (78 g/mol) = <em>2,57 g of Al(OH)₃ ≡ mass of precipitate</em>

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I hope it helps!

<em> </em>

3 0
3 years ago
A sample of aluminum has mass 26.98 g and has a density of
kherson [118]

Answer:

9.99L

Explanation:

you can see the answer at the pic

8 0
3 years ago
Read 2 more answers
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