Question: A. The state highway patrol radar guns use a frequency of 9.15 GHz. If you're approaching a speed trap driving 30.1 m/s, what frequency shift will your FuzzFoiler 2000 radar detector see?
B. The radar gun measures the frequency of the radar pulse echoing off your car. By what percentage is the measured frequency different from the original frequency? (Enter a positive number for a frequency increase, negative for a decrease. Just enter a number, without a percent sign.)?
Answer:
The frequency change percentage is 9.94%
Explanation:
The frequency shift can be calculated as follows.

= 
=9.95 GHz
So the frequency change seen by the detector is 9.95 - 9.05
% difference
= 9.94%
Answer:
0.14594 g/cm³
Explanation:
Density = Mass / Volume
Mass = 5400 g
Volume = 0.37 m³
Density = M /V
volume = 0.37 m³ = 37000 cm³
Density = 
= 0.14594 g/cm³
Answer:
option A is correct as 1 yard consist of 0.9144 meter which is less than one meter
Explanation:
from the above given statement option 1 is true
1 yard is equal to 0.9144 meter
while
1 mile is equal to 1.60934 km
1 foot is equal to 30.48 centimeter
1 inch is equal to 2.54 centimeter
therefore all these units [left one] are larger than their respective conversion [ right one unit]
therefore option A is correct as 1 yard consist of 0.9144 meter which is less than one meter
<span> the speed of sound in air is directly proportional to the temperature of the air. The speed of sound depends on the temperature of the surrounding air, this can be represented by a speed of sound in air formula: v = 331m/s + 0.6m/s/C * T (where T is temperature)</span>