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inysia [295]
3 years ago
14

If you had a 0.5 M KCl solution, how much solute would you have in moles, and what would the solute be?

Chemistry
1 answer:
Svetradugi [14.3K]3 years ago
6 0

Answer:

37.25 grams/L.

Explanation:

  • Molarity (M) is defined as the no. of moles of solute dissolved per 1.0 L of the solution.

<em>M = (no. of moles of KCl)/(volume of the solution (L))</em>

<em></em>

∵ no. of moles of KCl = (mass of KCl)/(molar mass of KCl)

∴ M = [(mass of KCl)/(molar mass of KCl)]/(volume of the solution (L))

∴ (mass of KCl)/(volume of the solution (L)) = (M)*(molar mass of KCl) = (0.5 M)*(74.5 g/mol) = 37.25 g/L.

<em>So, the grams/L of KCl = 37.25 grams/L.</em>

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The equation for your buffer equilibrium is:

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OH⁻(aq) + H₃O⁺(aq) ⟶ 2H₂O(ℓ)

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1. Balanced chemical for the given chemical reaction is :

2SO_2(g) +O_2(g) +2H_2O(l) \rightarrow  2H_2SO_4(aq)

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number of mole of oxygen required=6.25 mol

Explanation:

1. Balanced chemical for the given chemical reaction is :

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