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Greeley [361]
3 years ago
15

A hot-air balloon has a volume of 440 × 10^3 ^3. Calculate the buoyant force that the surrounding cold air exerts on the balloon

? Given that the density of the surrounding air is 2.58 kg/^3.
Physics
1 answer:
siniylev [52]3 years ago
3 0

Answer:

Explanation:

Given that,

The volume of the balloon is

V = 440 × 10³ m³

Buoyant force F?

Given the density of the surrounding to be 2.58 kg/m³

ρ = 2.58 kg/m³

The buoyant force is the weight of water displaced and it is calculated using

F_b = ρVg

Where

F_b is buoyant force

ρ is density

V is the volume of the liquid displace.

g is the acceleration due to gravity

Then,

F_b = ρVg

F_b = 2.58 × 440 × 10³ × 9.81

F_b = 1.1 × 10^7 N

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The intensity of light from a star varies inversely as the square of the distance. If you lived on a planet ten times farther aw
frosja888 [35]

Answer:

the intensity of the sun on the other planet is a hundredth of that of the intensity of the sun on earth.

That is,

Intensity of sun on the other planet, Iₒ = (intensity of the sun on earth, Iₑ)/100

Explanation:

Let the intensity of light be represented by I

Let the distance of the star be d

I ∝ (1/d²)

I = k/d²

For the earth,

Iₑ = k/dₑ²

k = Iₑdₑ²

For the other planet, let intensity be Iₒ and distance be dₒ

Iₒ = k/dₒ²

But dₒ = 10dₑ

Iₒ = k/(10dₑ)²

Iₒ = k/100dₑ²

But k = Iₑdₑ²

Iₒ = Iₑdₑ²/100dₑ² = Iₑ/100

Iₒ = Iₑ/100

Meaning the intensity of the sun on the other planet is a hundredth of that of the intensity on earth.

3 0
4 years ago
A reaction occurs in which carbon combines with oxygen to form carbon dioxide. Is this a chemical reaction or a nuclear reaction
Tatiana [17]

Answer:

A. This is a chemical reaction because only the electrons were rearranged.

Explanation:

A.P.E.X

4 0
3 years ago
Read 2 more answers
A 500kg car skids to a stop at a traffic light, leaving behind a 18.25m skid mark as it comes to a rest. Assuming that the car i
Nastasia [14]

Answer:

Coefficient of friction will be 0.587

Explanation:

We have given mass of the car m = 500 kg

Distance s = 18.25 m

Initial velocity of the car u = 14.5 m/sec

As the car finally stops so final velocity v = 0 m/sec

From second equation of motion

v^2=u^2+2as

0^2=14.5^2+2\times a\times 18.25

a=-5.76m/sec^2

We know that acceleration is given by

a=\mu g

5.76=\mu\times  9.81

\mu =0.587

So coefficient of friction will be 0.587

6 0
3 years ago
A gas occupies a volume of 20 cubic meters at 9,000 pascals. If the pressure is lowered to 5,000 pascals, what volume will the g
forsale [732]
We need to consider no change in the temperature of gas (isothermal transformation)

Volume and pressure are inversely proportional magnitudes, so we can write:

P_1.V_1=P_2.V_2\\
\\
9.20=5.V_2\\
\\
V_2=\frac{180}{5}=36 \ m^3
5 0
3 years ago
M/s
SashulF [63]

Answer:

a. Final velocity, V = 2.179 m/s.  

b. Final velocity, V = 7.071 m/s.

Explanation:

<u>Given the following data;</u>

Acceleration = 0.500m/s²

a. To find the velocity of the boat after it has traveled 4.75 m

Since it started from rest, initial velocity is equal to 0m/s.

Now, we would use the third equation of motion to find the final velocity.

V^{2} = U^{2} + 2aS

Where;

  • V represents the final velocity measured in meter per seconds.
  • U represents the initial velocity measured in meter per seconds.
  • a represents acceleration measured in meters per seconds square.
  • S represents the displacement measured in meters.

Substituting into the equation, we have;

V^{2} = 0^{2} + 2*0.500*4.75

V^{2} = 4.75

Taking the square root, we have;

V^{2} = \sqrt {4.75}

<em>Final velocity, V = 2.179 m/s.</em>

b. To find the velocity if the boat has traveled 50 m.

V^{2} = 0^{2} + 2*0.500*50

V^{2} = 50

Taking the square root, we have;

V^{2} = \sqrt {50}

<em>Final velocity, V = 7.071 m/s.</em>

8 0
3 years ago
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