1. Find the H.C.F. of 4x2y3 and 6xy2z.
Solution:
The H.C.F. of numerical coefficients = The H.C.F. of 4 and 6.
Since, 4 = 2 × 2 = 22 and 6 = 2 × 3 = 21 × 31
Therefore, the H.C.F. of 4 and 6 is 2
Answer:
The resultant velocity of the airplane is 213.41 m/s.
Step-by-step explanation:
Given that,
Velocity of an airplane in east direction, 
Velocity of wind from the north, 
Let east lies in the direction of the positive x-axis and north in the direction of the positive y-axis.
We need to find the resultant velocity of the airplane. Let v is the resultant velocity. It can be calculated as :


v = 213.41 m/s
So, the resultant velocity of the airplane is 213.41 m/s. Hence, this is the required solution.
Answer:
y=x+29/10 is the slope intercept form
Step-by-step explanation:
EXPLANATION
Let's see the facts:
The scale is---> 14 milimeters ----> 5 meters
Width = 42 milimeters
Applying the unitary method, the actual width of the pool is:

The width of the pool is 15m
I got ten. Here's the equation.
x = 1/2x + 5
<span>Subtract 1/2x from both sides to get all x's on one side </span>
<span>x - 1/2x = 1/2x - 1/2x + 5 </span>
<span>1/2x = 5 </span>
<span>Now multiple the left by 2 to get x, but since it's an equation, you need to also multiply the right by 2 to keep it =. </span>
<span>2 * 1/2x = 2 * 5 </span>
<span>x = 10 cats</span>