A cylinder is fitted with a piston, beneath which is a spring, as in the drawing. The cylinder is open to the air at the top. Fr
1 answer:
Answer:
x = 0.0537 m or 5.37 cm
Explanation:
Given:
spring constant'k'= 4900 N/m
radius 'r' =0.029 m
Area 'A' =r²π = 0.029²π => 2.6 x m²
Here, Pressure 'P' is given by,
Pressure = Force / Area
And we know that, for a spring :
F = kx, where k is the spring constant and x is the change in length.
P = kx/A
As P = 101325 Pa
101325 = 4900x / ( 2.6 x )
x = 0.0537 m or 5.37 cm
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Answer:
a. 15.4 seconds
b. 0.455 m/s
Explanation:
a. The carousel rotates at 0.13 rev/s.
This means that it takes the carousel 1 sec to make 0.13 of an entire revolution.
This means that time it will take to make a complete revolution is:
1 / 0.13 = 7.7 seconds
Therefore, the time it will take to make 2 revolutions is:
2 * 7.7 = 15.4 seconds
b. Let us calculate the linear velocity. Angular velocity is given as:
where v = linear velocity and r = radius
The radius of the circle is 3.5 m and the angular velocity is 0.13 rev/s, therefore:
0.13 = v / 3.5
v = 3.5 * 0.13 = 0.455 m/s
Linear velocity is 0.455 m/s
Answer:
<em>The equivalent resistance of the combination is R/100</em>
Explanation:
<u>Electric Resistance</u>
The electric resistance of a wire is directly proportional to its length. If a wire of resistance R is cut into 10 equal parts, then each part has a resistance of R/10.
Parallel connection of resistances: If R1, R2, R3,...., Rn are connected in parallel, the equivalent resistance is calculated as follows:
If we have 10 wires of resistance R/10 each and connect them in parallel, the equivalent resistance is:
This sum is repeated 10 times. Operating each term:
All the terms have the same denominator, thus:
Taking the reciprocals:
The equivalent resistance of the combination is R/100
(a) The momentum of each vehicle prior to collision is 80000 kgm/s for truck and 13500 kgm/s for car.
(b) The size of momentum is 93500 kgm/s and it will be directed towards South.
Explanation:
The mass of the truck moving due south is given as 4000 kg and the speed is 20 m/s. Similarly, the mass of the car moving due north is 1350 kg and the speed is 10 m/s.
(a) Then the momentum of each vehicle can be obtained by the product of mass with their respective speed.
Similarly, the momentum of car will be
So, the momentum of each vehicle prior to collision is 80000 kgm/s for truck and 13500 kgm/s for car.
(b) Since, after collision, the vehicles stick together, the momentum after collision will be equal to the total momentum of both the vehicles before collision. This is because, it will obey conservation of momentum.
Momentum of vehicles after collision = total momentum before collision
Momentum after collision = 80000+13500 = 93500 kgm/s.
The direction of the vehicles after collision will be towards south as the mass and speed of the truck is greater than car. So the impact or force exerted on the car by the truck will be greater and thus both the vehicles will be directed towards south after collision.
Thus, the size of momentum is 93500 kgm/s and it will be directed towards South.