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Katyanochek1 [597]
3 years ago
9

A cylinder is fitted with a piston, beneath which is a spring, as in the drawing. The cylinder is open to the air at the top. Fr

iction is absent. The spring constant of the spring is 4900 N/m. The piston has a negligible mass and a radius of 0.029 m. (a) When the air beneath the piston is completely pumped out, how much does the atmospheric pressure cause the spring to compress
Physics
1 answer:
Mazyrski [523]3 years ago
6 0

Answer:

x = 0.0537 m or 5.37 cm

Explanation:

Given:

spring constant'k'= 4900 N/m

radius 'r' =0.029 m

Area 'A' =r²π = 0.029²π => 2.6 x 10^{-3} m²

Here, Pressure 'P' is given by,

Pressure = Force / Area

And we know that, for a spring :

F = kx, where k is the spring constant and x is the change in length.

P = kx/A

As P = 101325 Pa

101325 = 4900x / ( 2.6 x 10^{-3})

x = 0.0537 m or 5.37 cm

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For this case we have that by definition, the momentum equation is given by:

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According to the data we have:

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Substituting:

p = 0.15 * 120\\p = 18 \frac {kg * m} {s}

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According to the data we have:

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shutvik [7]

Answer:

The man is on the verge of having a heart attack or a stroke.

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