Answer:
The correct option is;
c. Leaving the chuck key in the drill chuck
Explanation:
A Common safety issues with a drill press leaving the chuck key in the drill chuck
It is required that, before turning the drill press power on, ensure that chuck key is removed from the chuck. A self ejecting chuck key reduces the likelihood of the chuck key being accidentally left in the chuck.
It is also required to ensure that the switch is in the OFF position before turning plugging in the power cable
Be sure that the chuck key is removed from the chuck before turning on the power. Using a self-ejecting chuck key is a good way of insuring that the key is not left in the chuck accidentally. Also to avoid accidental starting, make sure the switch is in the OFF position before plugging in the cord. Always disconnect the drill from the power source when making repairs.
Answer:
Diesel cycle:
All diesel engine works on diesel cycle.It have four processes .These four processes are as follows
1-2.Reversible adiabatic compression
2-3.Heat addition at constant pressure
3-4.Reversible adiabatic expansion
4-1.Heat addition at constant volume
When air inters in the piston cylinder after that it compresses and gets heated due to compression after that heat addition take place at constant pressure after that power is produces when piston moves to bottom dead center.
From the diagram of P-v And T-s we can understand so easily.
Answer:Decay rate constant,k = 0.00376/hr
Explanation:
IsT Order Rate of reaction is given as
In At/ Ao = -Kt
where [A]t is the final concentration at time t and [A]o is the inital concentration at time 0, and k is the first-order rate constant.
Initial concentration = 80 mg/L
Final concentration = 50 mg/L
Velocity = 40 m/hr
Distance= 5000 m
Time taken = Distance / Time
5000m / 40m/hr = 125 hr
In At/ Ao = -Kt
In 50/80 = -Kt
-0.47 = -kt
- K= -0.47 / 125
k = 0.00376
Decay rate constant,k = 0.00376/hr
Answer:
hypoeutectoid
Explanation:
ferrite: pure form of iron
cementite: It is iron carbide with 93.3% iron and 6.67% carbon
hypoeutectoid: Eutectoid steel with carbon fraction less than 0.8%
hypereutectoid: Eutectoid Steel with carbon content more than 0.8%
For the mentioned iron-carbide alloy,
% of carbon in iron-carbide alloy= percentage of cementite × percentage of carbon in cementite
% of carbon in iron-carbide alloy= 0.09× 0.0667
= 0.6%
so the alloy is hypoeutectoid
