Answer:
true.
Explanation:
not only does it provide lumbar support, but has been scientifically proven to keep the blood flowing efficiently through the body, keeping you mind fresh.
Answer:
a) Under damped
Explanation:
Given that system is critically damped .And we have to find out the condition when gain is increased.
As we know that damping ratio given as follows

Where C is the damping coefficient and Cc is the critical damping coefficient.

So from above we can say that


From above relationship we can say when gain (K) is increases then system will become under damped system.
Answer:
the SI base unit of electrical current.
We can actually deduce here that making a airtight seal will take different format. You can:
- Use an epoxy-resin to create an airtight seal
- Create a glass-metal airtight seal
- Make a ceramic-metal airtight seal.
<h3>What is an airtight seal?</h3>
An airtight seal is actually known to be a seal or sealing that doesn't permit air or gas to pass through. Airtight seal are usually known as hermetic seal. They are usually applied to airtight glass containers but the advancement in technology has helped to broaden the materials.
We can see that epoxy-resin can used to create an airtight seal. They create airtight seals to copper, plastics, stainless steels, etc.
When making glass-metal airtight seal, the metal should compress round the solidified glass when it cools.
Learn more about airtight seal on brainly.com/question/14977167
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Answer:
the rate of heat loss is 2.037152 W
Explanation:
Given data
stainless steel K = 16 W 
diameter (d1) = 10 cm
so radius (r1) = 10 /2 = 5 cm = 5 × 
radius (r2) = 0.2 + 5 = 5.2 cm = 5.2 × 
temperature = 25°C
surface heat transfer coefficient = 6 6 W 
outside air temperature = 15°C
To find out
the rate of heat loss
Solution
we know current is pass in series from temperature = 25°C to 15°C
first pass through through resistance R1 i.e.
R1 = ( r2 - r1 ) / 4
× r1 × r2 × K
R1 = ( 5.2 - 5 )
/ 4
× 5 × 5.2 × 16 × 
R1 = 3.825 ×
same like we calculate for resistance R2 we know i.e.
R2 = 1 / ( h × area )
here area = 4
r2²
area = 4
(5.2 ×
)² = 0.033979
so R2 = 1 / ( h × area ) = 1 / ( 6 × 0.033979 )
R2 = 4.90499
now we calculate the heat flex rate by the initial and final temp and R1 and R2
i.e.
heat loss = T1 -T2 / R1 + R2
heat loss = 25 -15 / 3.825 ×
+ 4.90499
heat loss = 2.037152 W