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Debora [2.8K]
4 years ago
15

If the federal government imposed an obligation on Texas to retrofit all its oil and gas pipelines with modern technology to eli

minate any leaking of materials, but provided no funding for Texas to do so, this would be called a. a block grant. b. an unfunded mandate. c. a federal directive. d. a subsidized program.
Physics
1 answer:
sergeinik [125]4 years ago
3 0

c. a federal directive

Explanation:

This is a federal directive.

When a government imposes an obligation to be met by the subjects under it without proposing any form of help or funding whatsoever, it is called a directive.

Federal directive is the issuance of a written edict by the executive powers to control or compel a particular body to attain a certain goal.

These directives are not to be disputed or questioned. They are but one of the powerful tools used in governance.

learn more:

Right to privacy brainly.com/question/8775025

#learnwithBrainly

You might be interested in
Which of these would NOT produce visible light? A) flint B) lightning C) microwave D) sun
ioda

Answer:

A microwave

Explanation

The human retina can only detect incident light that falls in waves 400 to 720 nanometers long, so we can't see microwave or ultraviolet wavelengths. This also applies to infrared lights which has wavelengths longer than visible and shorter than microwaves, thus being invisible to the human eye.

6 0
3 years ago
Read 2 more answers
Please help me i dont get it
Dima020 [189]

The answers are:

<u>39:</u>

a - 1 mile

b - 0 miles

<u>40:</u>

a=-4\frac{m}{s^{2} }

<u>41:</u>

Displacement=3.60 miles\\Distance=5 miles

Why?

Solving 39:

To answer the questions, we need to remember that distance and displacement are different things. Distance refers to the total "ground" covered during motion, while displacement refers to how far is the object/body from its starting point.

So,

<u>39:</u>

a - the total distance traveled corresponds to the length of the track which is 1 mile.

b - The displacement is equal to 0 because they finished at the starting point,  the distance between the starting and the finishing point is equal to 0.

<u>40:</u>

We can solve the problem using one of the given equations:

a=\frac{v_f-v_i}{t}

Since we know all the information, we just need to substitute it into the equation:

a=\frac{v_f-v_i}{t}\\\\a=\frac{2\frac{m}{s} -16\frac{m}{s} }{3.5s}=\frac{-14\frac{m}{s} }{3.5s}\\\\a=-4\frac{m}{s^{2} }

So, the car's acceleration was -4m/s2 (the car was reducing its speed)

<u>41:</u>

We can solve the problem using one of the given equations (Pythagorean Theorem):

c^{2}=a^{2}+b^{2}

Displacement=\sqrt{(3mi(North))^{2}+(2miles(East))^{2}}\\\\Displacement=\sqrt{9+4}=\sqrt{13mi^{2}}=3.60miles

The distance will be:

Distance=3mi+2mi=5miles

Have a nice day!

3 0
3 years ago
The driver provides a constant force on the engine through the foot pedal. Eventually the van stops accelerating and reaches a c
Ad libitum [116K]

It follows from Newton's second law that there is some counteractive force that cancels out the force exerted by the engine - it's most likely drag due to air resistance in combination with static friction between the tires and the road. The car is moving at constant speed past a certain point, so the net force on the car is

∑ <em>F</em> = (force from engine) - (resistive forces) = 0

3 0
3 years ago
Two parallel wires carry equal currents in the opposite directions. Point A is midway between the wires, and B is an equal dista
zepelin [54]

Answer:

Complete Question:(missing part)

The current in the left wire having magnitude is  = 210 A

The Current in the right wire having magnitude is = 10 A

Answer:

a.B net = \frac{\mu_{0} }{2\pi(\frac{d}{2}) } (I_{1} +I_{2} )

Ratio = B 1/B 2 = 210/10 = 21

b.B net = \frac{\mu_{0} }{2\pi(\frac{d}{2}) } (\frac{I_{1}}{3}-I_{1}} )

Ratio = B 1/B 2 = 210/3 X10 = 7

Explanation:

Ratio of the magnitude of the magnetic field at point A to that at point B =?

The current in the left wire having magnitude is  = 210 A

The Current in the right wire having magnitude is = 10 A

distance between two wires = d

Given that both wires are carrying equal current but in opposite direction therefore

Magnetic field linked with the left wire at point A distance =d/2= according to biot savarts law

B = \frac{\mu_{0} \times I_{1} }{2\pi\times\frac{d}{2} }

Magnetic field linked with the right wire at point B distance =d/2

B = \frac{\mu_{0} \times I_{2} }{2\pi\times\frac{d}{2} }

Net magnetic field added

B net = B 1 + B 2

B net = \frac{\mu_{0} }{2\pi(\frac{d}{2}) } (I_{1} +I_{2} )

Ratio = B 1/B 2 = 210/10 = 21

Magnetic field linked to left wire at point B(d+ d/2)

B = \frac{\mu_{0} \times I_{1} }{2\pi\times\frac{3d}{2} }

Magnetic field linked to right wire at point B(d+ d/2)

B = \frac{\mu_{0} \times I_{2} }{2\pi\times\frac{3d}{2} }

Net magnetic field subtracted

B net = B 1 - B 2

B net = \frac{\mu_{0} }{2\pi(\frac{d}{2}) } (\frac{I_{1} }{3}-1 }  )

Ratio = B 1/B 2 = 210/3 X10 = 7

4 0
3 years ago
Will give Brianliest answer. help.
BARSIC [14]

Answer:

v₁ = 1.78 m/s

Explanation:

We can use the law of conservation of momentum here, as follows:

m_1u_1 + m_2u_2 = m_1v_1 + m_2v_2

where,

m₁ = mass of first object = 4.5 kg

m₂ = mass of second object = 6.2 kg

u₁ = initial speed of first (smaller) mass = 16 m/s

u₂ = initial speed of second (larger) mass = 0 m/s

v₁ = final speed of first (smaller) mass = ?

v₂ =  final speed of second (larger) mass = 10 m/s

Therefore,

(4.5\ kg)(16\ m/s)+(6.2\ kg)(0\ m/s)=(4.5\ kg)(v_1)+(6.2\ kg)(10\ m/s)\\70\ kgm/s - 62\ kgm/s = (4.5\ kg)v_1\\\\v_1 = \frac{8\ kgm/s}{4.5\ kg}\\\\

<u>v₁ = 1.78 m/s</u>

6 0
3 years ago
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