Skater N, 58.9 kg, is moving north at a speed of 7.8 m/s when she collides with Skater E, 72.6 kg, moving east at 3.5 m/s. The t
1 answer:
The direction of the skaters after the collision is 61 degrees.
<h3>Momentum of the skaters</h3>
The momentum of the skaters is calculated as follows;
P(N) = 58.9 x 7.8 = 459.42 kgm/s
P(E) = 72.6 x 3.5 = 254.1 kgm/s
<h3>Direction of the skaters after collision</h3>The direction of the skaters after the collision is calculated as follows;
Thus, the direction of the skaters after the collision is 61 degrees.
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The rate of change of velocity per unit time is called acceleration.
Its SI unit is m/s².
The recoil velocity of the astronaut is -0.070 m/s
Explanation:
We can solve this problem by using the principle of conservation of momentum: in fact, in absence of external forces, the total momentum of the astronaut-wrench system must be conserved.
At the beginning, their total momentum is zero:
(1)
Later, after the astronaut throws the wrench, the total momentum is
(2)
where
m = 0.725 kg is the mass of the wrench
v = 13.8 m/s is the velocity of the wrench
M = 143 kg is the mass of the astronaut
V is the recoil velocity of the astronaut
Since momentum is conserved, (1) = (2), and so we can find V:
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