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2 years ago

Which of the following objects has kinetic energy?

Physics

2 answers:

kotykmax [81]2 years ago

5 0

Answer:

Explanation:

A body has kinetic energy that is moving

RoseWind [281]2 years ago

4 0

Answer:

B - A hockey puck gliding across the ice.

Explanation:

All the other 3 options possess potential energy, where the object stands, sits, or lays where it is. There is only one option that is an example of kinetic energy. And that option is B.

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5. What is the percent composition of sulfur in H2SO4?

AVprozaik [17]

A. I looked it up and it should be somewhere around A

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2 years ago

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If a 2 kg spring is compressed by exerting a force of 10 newtons a distance of 50 cm how much work is done?

Elina [12.6K]

Convert cm into meters,
50/100=0.5m

work done= 10x0.5
=5J

we dont consider the weight of the spring as it acts downwards.

5 0

2 years ago

A bullet of mass 0.010 kg and speed of 200 m/s is brought to rest in a wooden block after penetrating a distance of 0.10 m. The

irina [24]

Answer:

W = 200 J

Explanation:

Work will be equal to the change in kinetic energy

W = ½mv² - 0

W = ½(0.010)200²

W = 200 J

7 0

2 years ago

A sprinter starts from rest and reaches a speed of 15 m/s in 4.25 s. Find his acceleration

kakasveta [241]

Answer:

a=3.53 m/s^2

Explanation:

Vo=0 m/s (because he is not moving at the start)

V1=15 m/s

t= 4.25 s

a = (V1-Vo) / t = 15/4.25 = 3.53 m/s^2

5 0

2 years ago

An ideal monatomic gas initially has a temperature of 300 K and a pressure of 5.79 atm. It is to expand from volume 420 cm3 to v

maxonik [38]

Answer:

a) The final pressure is 1.68 atm.

b) The work done by the gas is 305.3 J.

Explanation:

a) The final pressure of an isothermal expansion is given by:

$T = \frac{PV}{nR}$

$T_{i} = T_{f}$

$\frac{P_{i}V_{i}}{nR} = \frac{P_{f}V_{f}}{nR}$

Where:

$P_{i}$ : is the initial pressure = 5.79 atm

$P_{f}$ : is the final pressure =?

$V_{i}$ : is the initial volume = 420 cm³

$V_{f}$ : is the final volume = 1450 cm³

n: is the number of moles of the gas

R: is the gas constant

$P_{f} = \frac{P_{i}V_{i}}{V_{f}} = \frac{5.79 atm*420 cm^{3}}{1450 cm^{3}} = 1.68 atm$

Hence, the final pressure is 1.68 atm.

b) The work done by the isothermal expansion is:

$W = P_{i}V_{i}ln(\frac{V_{f}}{V_{i}}) = 5.79 atm*\frac{101325 Pa}{1 atm}*420 cm^{3}*\frac{1 m^{3}}{(100 cm)^{3}}ln(\frac{1450 cm^{3}}{420 cm^{3}}) = 305.3 J$

Therefore, the work done by the gas is 305.3 J.

I hope it helps you!

3 0

3 years ago