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3 years ago

Heat transmits readily through this

1 answer:

8 0

Can you be more specific?

...Diamond is the best conductor of heat, but heat also transmits readily through many other substances. Do you have multiple choice?

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Chromium(III) oxide can be prepared by heating chromium(IV) oxide in vacuo at high temperature: 4Cr02 —2Cr2O3 +02 The reaction o

kkurt [141]

<u>Answer:</u> The theoretical yield and percent yield of chromium (III) oxide is 434.72 grams and 92.6 % respectively.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

Given mass of $CrO_2$ = 480.1 g

Molar mass of $CrO_2$ = 84 g/mol

Putting values in equation 1, we get:

$\text{Moles of }CrO_2=\frac{480.1g}{84g/mol}=5.72mol$

For the given chemical equation:

$4CrO_2\rightarrow 2Cr_2O_3+O_2$

By Stoichiometry of the reaction:

4 moles of $CrO_2$ produces 2 moles of chromium (III) oxide

So, 5.72 moles of $CrO_2$ will produce = $\frac{2}{4}\times 5.72=2.86mol$ of chromium (III) oxide

Now, calculating the mass of chromium (III) oxide from equation 1, we get:

Molar mass of chromium (III) oxide = 152 g/mol

Moles of chromium (III) oxide = 2.86 moles

Putting values in equation 1, we get:

$2.86mol=\frac{\text{Mass of chromium (III) oxide}}{152g/mol}\\\\\text{Mass of chromium (III) oxide}=(2.86mol\times 152g/mol)=434.72g$

To calculate the percentage yield of chromium (III) oxide, we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Experimental yield of chromium (III) oxide = 402.4 g

Theoretical yield of chromium (III) oxide = 434.72 g

Putting values in above equation, we get:

$\%\text{ yield of chromium (III) oxide}=\frac{402.4g}{434.72g}\times 100\\\\\% \text{yield of chromium (III) oxide}=\%$

Hence, the theoretical yield and percent yield of chromium (III) oxide is 434.72 grams and 92.6 % respectively.

7 0

2 years ago

Which best describes how isotopes of the same element differ?

Tasya [4]

It would be C!!!!!!!!!!!!!

8 0

3 years ago

An orgo lab student named Bob wanted to synthesize an isoamyl acetate ester because it smells like bananas and he really likes t

mihalych1998 [28]

Answer:

The answer is "11.07 g".

Explanation:

Isoamyl alcohol is a reagent restriction

Isoamyl alcohol Moles:

$= \frac{7.5}{88.15} \\\\ =0.085$

Moles only with the shape of isoamyl acetate are equivalent to numbers.

Isoamyl acetate grams:

$= 0.085 \times 130.19\\\\ = 11.07 \ g$

3 0

3 years ago

Answer plsssss I’m dumb

aev [14]

Answer:

bottom middle

middle top

top bottom

Explanation:

4 0

3 years ago

How many electrons can the innermost shell of an atom have?

ss7ja [257]

There can only be two electrons in the innermost shell of an atom so b is the correct answer

5 0

3 years ago