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Over [174]
3 years ago
10

Atoms That have a positive charge will be attracted to atoms with a ___ charge.

Chemistry
1 answer:
san4es73 [151]3 years ago
3 0

Answer:

Opposites attract, It will be attracted to a negative charge

Explanation:

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Name one object that would be considered a gas. Describe how the atoms move in a gas.
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Answer:

gas vibrate and move freely at high speeds. liquid vibrate, move about, and slide past each other. solid vibrate (jiggle) but generally do not move from place to place.

Explanation:

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Approximately how much more energy is released in a 6.5 richter magnitude earthquake than in one with magnitude 5.5?
Elanso [62]
Answer: (C) 30 times

Richter scale is used to determine the magnitude of an earthquake from the arrival time of P and S waves. It determines the total amount of energy released during an earthquake.
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3 years ago
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A beaker contains a 25 ml solution of an unknown monoprotic acid that reacts in a 1:1 stoichiometric ratio with naoh. titrate th
yuradex [85]

<u>Given:</u>

Volume of the unknown monoprotic acid (HA) = 25 ml

<u>To determine: </u>

The concentration of the acid HA

<u>Explanation:</u>

The titration reaction can be represented as-

HA + NaOH → Na⁺A⁻ + H₂O

As per stoichiometry: 1 mole of HA reacts with 1 mole of NaOH

At equivalence point-

moles of HA = moles of NaOH

For a known concentration and volume of added NaOH we have:

moles of NaOH = M(NaOH) * V(NaOH)

Thus, the concentration of the unknown 25 ml (0.025 L) of HA would be-

Molarity of HA = moles of HA/Vol of HA

Molarity of HA = M(NaOH)*V(NaOH)/0.025 L


5 0
3 years ago
A sample of an unknown compound is vaporized at 180.°C. The gas produced has a volume of 2010.mL at a pressure of 1.00atm, and i
stiv31 [10]

<u>Answer:</u> The molar mass of the given unknown compound is 50.5 g/mol.

<u>Explanation:</u>

To calculate the volume of water, we use the equation given by ideal gas, which is:

PV=nRT

or,

PV=\frac{m}{M}RT

where,

P = pressure of sample = 1.00 atm

V = volume of sample = 2010 mL = 2.010 L   (Conversion factor: 1 L = 1000 mL)

m = Given mass of unknown compound = 2.73 g

M = Molar mass of unknown compound = ? g/mol

R = Gas constant = 0.0820\text{ L atm }mol^{-1}K^{-1}

T = temperature of sample = 180^oC=[180+273]K=453K

Putting values in above equation, we get:

1.00atm\times 2.010L=\frac{2.73g}{M}\times 0.0820\text{ L atm }mol^{-1}K^{-1}\times 453K\\\\V=50.45g/mol

Rounding off to 3 significant figures, we get the molar mass to be 50.5 g/mol.

Hence, the molar mass of the given unknown compound is 50.5 g/mol.

8 0
3 years ago
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