Answer:
The circular solar orbital speed at 4.0AU is 1/4( one fourth) that at 1.0AU
Explanation:
am = mvr= angular momentum
am4= 4mvt
am1= mvp1
Vt=1/4vp
Vp=4vt
am1= 4mvt
am1=am4
The circular solar orbital speed at 4.0AU is 1/4 (one fourth) that at 1.0AU
Draw a right triangle so that its hypotenuse is 600 ft. The adjacent side is below the vertical, and it makes an angle of 75° with the hypotenuse.
Let h = height of the right triangle.
By definition,
sin75° = h/600
h = 600*sin75° = 579.555 = 580 ft (nearest ft)
Answer: 580 ft (nearest foot)
If friction is acting along the plane upwards
then in this case we will have
For equilibrium of 100 kg box on inclined plane we have
also for other side of hanging mass we have
now we have
In other case we can assume that friction will act along the plane downwards
so now in that case we will have
also we have
now we have
<em>So the range of angle will be 23.45 degree to 37 degree</em>
“We LoVeEe BiDeN bEcAuSe hIs HeAlThCaRe iSn’T FrEeEeE!”
Answer:
rock of mass m is dropped to the ground from a height h. A second rock, with mass 2m, is dropped from the same height. When the second rock strikes the ground, what is its kinetic energy? (a) Twice that of the first rock, (b) four times that of the first rock, (c) same as that of the first rock, (d) half as much as that of the first rock, (e) impossible to determine.
