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Wewaii [24]
3 years ago
11

A railroad car of mass 20000 kg and velocity 5.0 m s to the right collides completely elastically in a head on collision with a

second car of mass 10000 kg traveling at 1.0 m s to the left and couples to it What fraction of the initial kinetic energy is still retained by the cars after the collision
Physics
1 answer:
Montano1993 [528]3 years ago
4 0

Answer:

OMG IM ON THE SAME QUESTION

Explanation:

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What happens to the mass of a metal ball if its heated?
erik [133]
<span>Mass doesn't change when the temperature of the ball changes.
(Unless, of course, it gets so hot that it melts, and part of it falls off
and rolls under the table.)</span>
5 0
3 years ago
Read 2 more answers
A 32.0 kg wheel, essentially a thin hoop with radius 1.20 m, is rotating at 280 rev/min. It must be brought to a stop in 15.0 s.
elena-14-01-66 [18.8K]

Answer:

A) Must be done 19806.62 joules of work.

B) The average power is 1320.44 Watts.

Explanation:

A) First, we're going to use the work-energy theorem that states total work (W) done on an object is equal to the change in its kinetic energy (\Delta K):

W=\Delta K = K_{f}-K_{i} (1)

So, all we must do is to find the change on kinetic energy. Because we're working with rotational body, we should use the equation K=\frac{I\omega^{2}}{2} for the kinetic energy so:

\Delta K=\frac{I(\omega_{f})^{2}}{2}-\frac{I(\omega_{i})^{2}}{2} (2)

with \omega_{i} the initial angular velocity, \omega_{f} the final angular velocity (is zero because the wheel stops) and I the moment of inertia that for a thin hoop is I=MR^{2}, using those on (2)

\Delta K=0-\frac{MR^{2}(\omega_{i})^{2}}{2} (3)

By (3) on (1):

W= \frac{MR^{2}(\omega_{i})^{2}}{2} = \frac{(32.0)(1.2)^{2}(29.32)^{2}}{2}

W=19806.62\,J

B) Average power is work done divided by the time interval:

P=\frac{W}{\Delta t}=\frac{19806.62}{15.0}

P=1320.44\,W

NOTE: We use the relation 1rpm*\frac{2\pi}{60s}=\frac{rad}{s} to convert 280 rev/min(rpm) to 29.32 rad/s

4 0
4 years ago
What are the two principle advantages of telescopes over eyes?
Stells [14]

Answer:

i) Telescopes can be used to view far distant objects but the human eye can't view far distant objects.

ii) Telescopes uses two convex lenses producing a magnified image while the human eye only possesses one convex lens (image seen are smaller than that viewed under telescopes)

Explanation:

The telescopes can be used to view far distant objects due to their presence of two convex lenses. The two convex lenses are the objective lens (lens closer to object) and the eye piece lens (lens closer to eye). The object to be viewed forms an intermediate image first before the final image is seen using the eye piece lens.

The human eye only possess one convex lens and as such cannot view far ranged objects.

8 0
4 years ago
The slight negative charge at one end of one water molecule is attracted to the slight positive charge of another water molecule
aleksley [76]
Electromagnetic force. It is where alike forces ( negative, negative & positive , positive) repel and opposite forces ( negative & positive ) attract.
Hopes this helped
7 0
3 years ago
1. How much heat must be absorbed by 375 grams of water to raise its
antiseptic1488 [7]

Answer:

39225J

Explanation:

Given parameters:

Mass of water  = 375grams of water

Change in temperature  = 25°C

Specific heat capacity of water  = 4.184J/g°C

Unknown:

Amount of heat absorbed  = ?

Solution:

To solve this problem, we use the expression below:

      H  = m c Ф  

H is the heat absorbed

m is the mass

c is the specific heat capacity

Ф is the change in temperature

  Insert the parameters and solve;

      H  = 375 x 4.184 x (25) = 39225J

5 0
3 years ago
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