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liberstina [14]
4 years ago
12

Which statement is true with respect to the investigation? The student investigated only the physical properties of lead. The st

udent investigated only the chemical properties of lead. The student investigated more physical properties than chemical properties of lead. The student investigated more chemical properties than physical properties of lead.
Chemistry
2 answers:
Oksi-84 [34.3K]4 years ago
6 0

The question is incomplete, the complete question is;

A student investigated some properties of lead and recorded the findings in the table below. Property Observation Color Dull gray Density 11.3 g/cm3 Volume of sample 3 cm3 Melting point 327°C Reaction with air Lead oxide forms on the surface Electrical conductivity Conducts some electricity Which statement is true with respect to the investigation?

A. The student investigated only the physical properties of lead.  

B. The student investigated only the chemical properties of lead.  

C. The student investigated more physical properties than chemical properties of lead.  

D. The student investigated more chemical properties than physical properties of lead.

Answer:

The student investigated more physical properties than chemical properties of lead.

Explanation:

If we look at the things mentioned in the question as regards the approach of the student towards the study of lead, we will discover that he/studied;

Colour, density, volume, melting point and electrical conductivity which are all physical properties. Physical properties of a substance does not involve chemical reactions of the substance under study.

The only chemical property studied by the student is its formation of an oxide- lead oxide with air as follows;

2Pb(s) + O₂(g) → 2PbO(s)

Thus we can safely conclude that; the student investigated more physical properties than chemical properties of lead.

aivan3 [116]4 years ago
5 0

Answer

It's D.

Explanation:

Just incase u have limited time. Have a nice day!

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OB. Energy transfer would occur between the copper bars and the surroundings.

Explanation:

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A 25.0 mL sample of a solution of a monoprotic acid is titrated with a 0.115 M NaOH solution. The end point was obtained at abou
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Answer:

The concentration of the acid is about 0.114 M (option E)

Explanation:

Step 1: Data given

Volume of the monoprotic acid = 25.0 mL = 0.025 L

Molarity of the monoprotic acid = ?

Molarity of the NaOH solution = 0.115 M

Volume NaOH = 24.8 mL = 0.0248 L

Step 2: Calculate the concentration

a*Cb * Vb = b * Ca * Va

⇒ a = the coeficient of NaOH = 1

⇒ Cb = the molarity of the acid = TO BE DETERMINED

⇒ Vb = the volume of the acid = 0.025 L

⇒ b = the coefficient of the acid = monoprotic = 1

⇒ Ca = the moalrity of NaOH = 0.115 M

⇒ Va = the volume of NaOH = 0.0248 L

1 * Cb * 0.025 = 1 * 0.115 * 0.0248

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5 0
4 years ago
The reaction of NH3 and O2 forms NO and water. The NO can be used to convert P4 to P4O6, forming N2 in the process. The P4O6 can
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Answer : The mass of PH_3 produced from the reaction is, 0.651 grams.

Explanation :

The chemical reactions used are:

(1) 4NH_3+5O_2\rightarrow 4NO+6H_2O

(2) 6NO+P_4\rightarrow P_4O_6+3N_2

(3) P_4O_6+6H_2O\rightarrow 4H_3PO_4

(4) 4H_3PO_4\rightarrow PH_3+3H_3PO_4

First we have to calculate the moles of NH_3

\text{Moles of }NH_3=\frac{\text{Mass of }NH_3}{\text{Molar mass of }NH_3}

Molar mass of NH_3 = 17 g/mol

\text{Moles of }NH_3=\frac{1.95g}{17g/mol}=0.115mol

Now we have to calculate the moles of NO

From the balanced chemical reaction 1, we conclude that:

As, 4 moles of NH_3 react to give 4 moles of NO

So, 0.115 moles of NH_3 react to give 0.115 moles of NO

Now we have to calculate the moles of P_4O_6

From the balanced chemical reaction 2, we conclude that:

As, 6 moles of NO react to give 1 moles of P_4O_6

So, 0.115 moles of NO react to give \frac{0.115}{6}=0.0192 moles of P_4O_6

Now we have to calculate the moles of H_3PO_4

From the balanced chemical reaction 3, we conclude that:

As, 1 moles of P_4O_6 react to give 4 moles of H_3PO_4

So, 0.0192 moles of P_4O_6 react to give 0.0192\times 4=0.0768 moles of H_3PO_4

Now we have to calculate the moles of PH_3

From the balanced chemical reaction 4, we conclude that:

As, 4 moles of H_3PO_4 react to give 1 moles of PH_3

So, 0.0768 moles of H_3PO_4 react to give \frac{0.0768}{4}=0.0192 moles of PH_3

Now we have to calculate the mass of PH_3

\text{ Mass of }PH_3=\text{ Moles of }PH_3\times \text{ Molar mass of }PH_3

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\text{ Mass of }PH_3=(0.0192moles)\times (33.9g/mole)=0.651g

Therefore, the mass of PH_3 produced from the reaction is, 0.651 grams.

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