It is metal that is why you cook things mainly with metal pots
The empirical formula of the compound is SiCl₄.
<h3>Empirical formula of the compound</h3>
mass of silicon = 28 g/mol
mass of chlorine = 35.5 g/mol
<h3>molar ration: </h3>
Si = 8.56/28 = 0.306
Cl = 43.2/35.5 = 1.216
<h3>Combining ratio</h3>
Si = 0.306/0.306 = 1
Cl = 1.216/0.306 = 4
empirical formula = SiCl₄
Thus, the empirical formula of the compound is SiCl₄.
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Answer:
Here is a bunch of info from my lesson to help you out...
Explanation:
All matter has physical and chemical properties. Physical properties are characteristics that scientists can measure without changing the composition of the sample under study, such as mass, color, and volume (the amount of space occupied by a sample). Chemical properties describe the characteristic ability of a substance to react to form new substances; they include its flammability and susceptibility to corrosion. All samples of a pure substance have the same chemical and physical properties. For example, pure copper is always a reddish-brown solid (a physical property) and always dissolves in dilute nitric acid to produce a blue solution and a brown gas (a chemical property).
Physical properties can be extensive or intensive. Extensive properties vary with the amount of the substance and include mass, weight, and volume. Intensive properties, in contrast, do not depend on the amount of the substance; they include color, melting point, boiling point, electrical conductivity, and physical state at a given temperature. For example, elemental sulfur is a yellow crystalline solid that does not conduct electricity and has a melting point of 115.2 °C, no matter what amount is examined (Figure 1.3.1
1.3.
1
). Scientists commonly measure intensive properties to determine a substance’s identity, whereas extensive properties convey information about the amount of the substance in a sample.
Explanation:
first find the value of Ph
from Ph= -log[H+]
ph=-log[1.7x10^-8]=7.769
find Poh from 14=ph+poh
14=7.769+poh
Poh=6.231 part a
for part b the same as part a from the above procedure
