Answer:
I only really know the "How do we use these EM waves in our lives?" part srry
Explanation:
EM waves are used to make sure you cellphone, radio, TV, and etc. have service/ connection.
Answer: 4.4 cm.
Explanation:
Rise of water in the smaller tube= h1=8.8 centimeter(cm)
Radius of the smaller tube= r
Rise of water in the larger tube= h2 (in centimeter).
The radius of the larger tube is twice that of the smaller tube means that;
The radius in the larger tube is 2r ( 2 multiply by the radius r, of the smaller tube)
Using Jurin's law;
height or rise of liquid is inversely proportional to its radius, r.
That is; hr= constant.
Therefore, we have;
h1 × r1 = h2 × r2.
Rise in smaller tube × radius of the smaller tube = height of the larger tube × radius of the larger tube.
8.8 cm × r = h2 × 2r
= (8.8cm)r = (h2) 2r
Divide both sides by 2r, we then have;
8.8cm r/ 2r = h2
h2= 4.4cm
Therefore, the height or rise in large tube is half of that of the smaller tube.
There are 10⁹ picoseconds in 1 Ms
1 picosecond= 10¹² s
1 Ms = 10⁻³ s
so the number of picoseconds in one Ms=(10⁻³ s/1 Ms) * (10¹² Ps/ 1 s)=10⁹
Thus there are 10⁹ picoseconds in 1 Ms
Answer:
The volume is decreasing at 160 cm³/min
Explanation:
Given;
Boyle's law, PV = C
where;
P is pressure of the gas
V is volume of the gas
C is constant
Differentiate this equation using product rule:
Given;
(increasing pressure rate of the gas) = 40 kPa/min
V (volume of the gas) = 600 cm³
P (pressure of the gas) = 150 kPa
Substitute in these values in the differential equation above and calculate the rate at which the volume is decreasing ( 
);
(600 x 40) + (150 x ) = 0
Therefore, the volume is decreasing at 160 cm³/min
