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Andre45 [30]
2 years ago
7

A skateboarder, starting from the top of a ramp 4,5 m above the ground, skates down the ramp. The mass of the skateboarder and h

is board is 65 kg
Physics
1 answer:
xz_007 [3.2K]2 years ago
3 0

Answer:

Kinetic energy is 2886.5Joule

  • <em><u>See image for solution</u></em>

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PLS HELP ASAP I NEED THIS BY TONIGHT
adoni [48]

Answer:

woahhh

Explanation:

7 0
3 years ago
On a straight road with the +x axis chosen to point in the direction of motion, you drive for 5 hours at a constant 20 miles per
Leviafan [203]

Answer:

v = 26.7 mph

Explanation:

During the first 5 hours, at a constant speed of 20 mph, we find the total displacement to be as follows:

Δx₁ = v₁*t₁ = 20 mph*5 h = 100 mi

Assuming we can neglect the displacement during the speeding up from 20 to 60 mph, we can find the the total displacement at 60 mph as follows:

Δx₂ = v₂*t₂ = 60 mph*1 h = 60 mi

So, the total displacement during all the trip wil be:

Δx = Δx₁ + Δx₂ = 100 mi + 60 mi = 160 mi

So we can find the the average velocity during the 6-hour period, applying the definition of average velocity, as follows:

v = Δx / Δt = 160 mi / 6 h = 26.7 mph

8 0
4 years ago
What's a cars net force if it's mass is 1500 kg and has a acceleration of 2 m/s (In Newton’s)
podryga [215]

Answer: 3,000 N

Explanation:

F = mass x acceleration

F = (1500 kg)(2 m/s²)

F = 3000 N

3 0
3 years ago
A bicycle wheel with radius 0.3 m rotates from rest to 3 rev/s in 5 s. What is the magnitude and direction of the total accelera
AlekseyPX

Answer:

Explanation:

Given

Radius of bicycle wheel r=0.3\ m

Initial angular velocity \omega _0=0

It rotates 3 revolution in 5 s therefore

\omega =2\pi 3=\6\pi =18.85\ rad/s

using \omega =\omega _0+\alpha t

where \alpha =angular\ acceleration

\omega =Final\ angular\ velocity

t=time

\alpha =\frac{18.85}{5}=3.77 rad/s^2

Total acceleration of any point will be a vector sum of tangential acceleration and centripetal acceleration

\omega at t=1

\omega =0+3.77\times 1=3.77 rad/s

a_c=\omega ^2\cdot r

a_c=(3.77)^2\cdot 0.3=4.26 m/s^2

Tangential acceleration a_t=\alpha \times r

a_t=3.77\times 0.3=1.13 m/s^2

a_{net}=\sqrt{a_t^2+a_c^2}

a_{net}=\sqrt{(1.13)^2+(4.26)^2}

a_{net}=4.41 m/s^2

                       

7 0
3 years ago
What change will most likely increase the strength of a magnetic field produced by an electromagnet? a. Reduce the number of tur
Anettt [7]

Answer:

Option D

Explanation:

When another battery is added to the circuit, the power supplied through the coil and to the magnet becomes greater leading to stronger magnetic field lines being produced.

7 0
3 years ago
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