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Alborosie
3 years ago
5

During ____, the chromatin condenses to make ____.

Chemistry
1 answer:
Mkey [24]3 years ago
4 0
Prophase, chromosomes
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What are three possible blood type alleles?
Keith_Richards [23]

Answer:

Three possible blood type alleles are Iᴬ, Iᴮ and i

Explanation:

Iᴬ, Iᴮ and i are three possible blood type alleles.

Iᴬ and Iᴮ are known as co-dominant, and The i allele is recessive.

Thus, Three possible blood type alleles are Iᴬ, Iᴮ and i

<u>-TheUnknownScientist</u>

8 0
3 years ago
Read 2 more answers
A. How the molecules in a solid, liquid and gas compare to each other.
andre [41]
A. The molecules of solids are close together and compact, liquids are spread out but not too far apart, and gas molecules are really far apart.

B. Increase in temperature causes pressure to go up. Decrease in temperature cause pressure to go down
8 0
3 years ago
What factors do you think should be considered in selecting a metal to use to reclaim copper? Which factor do you think is the m
Lana71 [14]

Answer:

Aluminum

Explanation:

<h3> <em>Aluminum would be the best choice to reuse  copper from the copper chloride solution because it  In the aluminum–copper reaction, the chloride ions help remove the aluminum oxide coating so that a reaction can take place through the oxidation of aluminum and the reduction of copper ions.The aluminum–copper chloride reaction is a simplified version of a waste reclamation and reduction strategy for handling toxic-waste materials. </em></h3>
7 0
3 years ago
216 J of energy is required to raise the temperature of a piece of aluminum from 15.0º C to to 35º C.
ddd [48]

Answer: 12g

Explanation:

The amount of energy (Q) required to raise the temperature of a substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Given that:

Q = 216 joules

Mass of aluminium = ? (let unknown value be Z)

C = 0.90 JºC-1g-1

Φ = (Final temperature - Initial temperature)

= 35°C - 15°C = 20°C

Then, Q = MCΦ

216 J = Z x 0.90 JºC-1g-1 x 20°C

216 J = Z x 18 J°g-1

Z = (216J/18 J°g-1)

Z = 12g

Thus, the mass of the aluminium is 12grams

8 0
4 years ago
How many moles of KBr are present in 500 ml of a 0.8 M KBr solution?
faltersainse [42]

Answer:

2) 0.4 mol

Explanation:

Step 1: Given data

  • Volume of the solution (V): 500 mL
  • Molar concentration of the solution (M): 0.8 M = 0.8 mol/L

Step 2: Convert "V" to L

We will use the conversion factor 1 L = 1000 mL.

500 mL × 1 L/1000 mL = 0.500 L

Step 3: Calculate the moles of KBr (solute)

The molarity is the quotient between the moles of solute (n) and the liters of solution.

M = n/V

n = M × V

n = 0.8 mol/L × 0.500 L = 0.4 mol

4 0
3 years ago
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