Question

If 725 ml of N² gas is at 1 atm, what volume will it have at 1.4 atm?​

Answer 1

Answer:

517.86 mL

Explanation:

Boyle's Law Formula

• P₁V₁ = P₂V₂

Here :

• V₁ = 725 mL
• P₁ = 1 atm
• P₂ = 1.4 atm

Solving

• V₂ = P₁V₁/P₂
• V₂ = 1 × 725 / 1.4
• V₂ = 517.86 mL

Answer 2

Answer:

518 mL

Explanation:

We can solve this using Boyle's Law Formula

P1V1 = P2V2

where p1 = initial pressure, p2 = final pressure, v1 = initial volume and v2 = final volume

here , the initial pressure is 1 atm and the initial volume is 725mL

we are given the final pressure 1.4 and we need to find the final volume

so we have p1v1 = p2v2

==> plug in p1 = 1 , v1 = 725 mL and p2 = 1.4

(1)(725) = (1.4)v2

==> multiply 1 and 725

725 = (1.4)(v2)

==> divide both sides by 1.4

v2 = 518

N2 would have a volume of 518mL at 1.4atm