Answer:
32.73%
Explanation:
To solve this problem, first find the molar mass of Al(OH)₃.2H₂O
Atomic mass of Al = 27g/mol
O = 16g/mol
H = 1g/mol
Molar mass = 27 + 3(16 + 1) + 2(2(1) + 16)
= 27 + 51 + 36
= 114g/mol
Percentage composition =
x 100 = 32.73%
The reaction between the lead iodide, PbI2 and sodium carbonate, Na2CO3, will form the chemical compounds, sodium iodide and lead carbonate as shown below.
PbI2 + Na2CO3 --> NaI + PbCO3
The white precipitate formed in the reaction is PbCO3.
The question is incomplete, the question is;
Which drawing best accounts for the polarity of methanol, CH3OH, and the bond polarities that make a major contribution to the overall molecular polarity?
A) drawing (1) B) drawing (2)
D) drawing (4) C) drawing (3)
Answer:
B) drawing (2)
Explanation:
In Chemistry, the direction of dipole is shown from positive end to negative end.
The image that contains the options in the question asked has been attached.
We can see in image 2 that the oxygen atom was correctly designated as the negative end of the dipole while the carbon and hydrogen atoms were each designated as positive ends of the dipole in accordance with the magnitude of electronegativity difference between the two atoms. The net dipole moment is now taken in the direction shown in image 2. This is the correct answer.
Answer:
Ethanol (boiling point 78°C) and methanol (boiling point 65°C) are two miscible liquids. There is only a small difference in their boiling points. These two liquids are separated from their mixture by fractional ths distillation.
When vapours of the mixture pass through the fractionating column, repeated liquefaction and vapourisation take place. Subsequently, the vapours of low boiling methanol enter the condenser from the fractionating column, condense to liquid and get collected in the round bottomed flask first. Similarly, ethanol with higher boiling point can be collected later in another round bottomed flask.