<h2>
Answers:</h2>
The energy of a photon is given by the following formula:
(1)
Where:
is the Planck constant
is the frequency
Now, the frequency has an inverse relation with the wavelength :
(2)
Where is the speed of light in vacuum
Substituting (2) in (1):
(3)
<u>Knowing this, let's begin with the answers:
</u>
<h2>(a) Microwave: 50.00 cm
</h2><h2 />
For
<h2>(b) Visible: 500 nm
</h2><h2 />
For
<h2>(c) X-ray: 0.5 nm
</h2><h2 />
For
As we can see, as the wavelength decreases, the energy increases.
Answer:
r = 2.56 10⁻¹² m
Explanation:
For this exercise let's use energy conservation
Starting point, proton too far
Em₀ = K = ½ m v²
Final point. When proton is stop
Emf = U = k q₁ q₂ / r
How energy is conserved
Em₀ = Emf
½ m v² = k q₁ q₂ / r
r = 2k q₁ q₂ / m v²
Let's calculate
r = 2 8.99 10⁸ 1.6 10⁻¹⁹ 1.82 10⁻¹⁸ / (1.67 10⁻²⁷ (3.5 10⁵)² )
r = 2.56 10⁻¹² m
Answer:
0.4 ohms.
Explanation:
From the circuit,
The voltage reading in the voltmeter = voltage drop across each of the parallel resistance.
1/R' = 1/R1+1/R2
R' = (R1×R2)/(R1+R2)
R' = (2.4×1.2)/(2.4+1.2)
R' = 2.88/3.6
R' = 0.8 ohms.
Hence the current flowing through the circuit is
I = V'/R'................ Equation 1
Where V' = voltmeter reading
I = 6/0.8
I = 7.5 A
This is the same current that flows through the variable resistor.
Voltage drop across the variable resistor = 9-6 = 3 V
Therefore, the resistance of the variable resistor = 3/7.5
Resistance = 0.4 ohms.