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Scilla [17]
3 years ago
15

When a planet orbits the Sun, the

Physics
2 answers:
Nikitich [7]3 years ago
8 0
I think it’s A not sure but sorry if not correct!
Anna [14]3 years ago
6 0
I’m not sure I think it’s A
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How is the mass number calculated for an element?
natali 33 [55]
<span># of protons + # of neutrons = atomic mass</span>
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4 years ago
A student made the table shown to list some contact and non-contact forces. Examples of Forces Contact Forces Non-Contact Forces
aleksandr82 [10.1K]

Answer:

the second one is incorrect

Explanation:

I am smart and took the test

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3 years ago
Two balls with equal masses, m, and equal speed, v, engage in a head on elastic collision. what is the final velocity of each ba
Allushta [10]
The collision is elastic. This means that both momentum and kinetic energy are conserved after the collision.

- Let's start with conservation of momentum. The initial momentum of the total system is the sum of the momenta of the two balls, but we should put a negative sign in front of the velocity of the second ball, because it travels in the opposite direction of ball 1. So ball 1 has mass m and speed v, while ball 2 has mass m and speed -v:
p_i = p_1-p_2 = mv-mv =0
So, the final momentum must be zero as well:
p_f = 0
Calling v1 and v2 the velocities of the two balls after the collision, the final momentum can be written as
p_f = mv_1 + mv_2 = 0
From which
v_1 = -v_2

- So now let's apply conservation of kinetic energy. The kinetic energy of each ball is \frac{1}{2} mv^2. Therefore, the total kinetic energy before the collision is
K_i = \frac{1}{2} mv^2 +  \frac{1}{2} mv^2 = mv^2
the kinetic energy after the collision must be conserved, and therefore must be equal to this value:
K_f = K_i = mv^2 (1)
But the final kinetic energy, Kf, is also
K_f =  \frac{1}{2} mv_1^2 +  \frac{1}{2}mv_2^2
Substituting v_1 = -v_2 as we found in the conservation of momentum, this becomes
K_f = mv_2 ^2
we also said that Kf must be equal to the initial kinetic energy (1), therefore we can write 
mv_2^2 = mv^2

Therefore, the two final speeds of the balls are
v_2 = v
v_1 = -v_2 = -v

This means that after the collision, the two balls have same velocity v, but they go in the opposite direction with respect to their original direction.

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3 years ago
SONAR was developed during World War II, to find submarines. Submarines were sneaking up on ships underwater and releasing torpe
Reika [66]
As long as you describe the chemical reactions within the torpedo and explain how torpedoes advanced modern warfare.
3 0
4 years ago
Read 2 more answers
Light of wavelength 578.0 nm is incident on a narrow slit. The diffraction pattern is viewed on a screen 62.5 cm from the slit.
yaroslaw [1]

Answer:

80.6\mu m

Explanation:

When light passes through a narrow slit, it produces a diffraction pattern on a distant screen, consisting of several bright fringes (constructive interference) alternated with dark fringes (destructive interference).

The formula to calculate the position of the m-th maximum in the diffraction pattern produced in the screen is:

y=\frac{m\lambda D}{d}

where

y is the distance of the m-th maximum from the central maximum (m = 0)

\lambda is the wavelength of light used

D is the distance of the screen from the slit

d is the width of the slit

In this problem, we have:

\lambda=578.0 nm = 578\cdot 10^{-9} m is the wavelength

D = 62.5 cm = 0.625 m is the distance of the screen

We know that the distance between the third order maximum (m=3) and the central maximum is 1.35 cm (0.0135 m), which means that

y_3 = 0.0135 m

For

m = 3

Therefore, rearranging the equation for d, we find the width of the slit:

d=\frac{m\lambda D}{y_3}=\frac{(3)(578\cdot 10^{-9})(0.625)}{0.0135}=80.3\cdot 10^{-6} m=80.6\mu m

8 0
4 years ago
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