All these resistors are in series so we can take the sum of them by:
Rtotal = R1 + R2 + R3......
So...
Rtotal = 2 + 3 + 4 + 6
Rtotal = 15
So now the total resistance in the circuit is 15 ohms and the potential difference applied to the circuit is 45 volts
Now we can use:
V = IR
Isolate for I
V/R = I
45/15 = I
I = 3 amps (A)
Yes because you intoxicated
Hope this helped :)
He has tendonitis. Hope this helps
To solve the problem it is necessary to take into account the concepts related to simple pendulum, i.e., a point mass that is suspended from a weightless string. Such a pendulum moves in a harmonic motion -the oscillations repeat regularly, and kineticenergy is transformed into potntial energy and vice versa.
In the given problem half of the period is equivalent to 1 second so the pendulum period is,
From the equations describing the period of a simple pendulum you have to
Where
g= gravity
L = Length
T = Period
Re-arrange to find L we have
Replacing the values,
In the case of the reduction of gravity because the pendulum is in another celestial body, as the moon for example would happen that,
In this way preserving the same length of the rope but decreasing the gravity the Period would increase considerably.
<h2>Answers:</h2>
<h2>1. Differraction Pattern:
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The diffraction pattern is that formed when a wave is deflected when it passes through an opening or encounters an obstacle.
When this occurs, the wave bends around the corners of the obstacle or passes through the opening of the slit that acts as an obstacle, forming multiple patterns with the shape of the aperture of the slit.
Note that the principal condition for the occurrence of this phenomena is that the obstacle must be comparable in size (similar size) to the size of the wavelength.
This means the smaller the slit or obstacle (diffracting object), the wider the resulting diffraction pattern, and the greater the obstacle, the narrower de resulting patter.
<h2>2. Diffraction Angle:
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Is the output resulting angle as measured from the surface that is normal (perpendicular) to the slit.
Now, if instead of a slit we have a diffraction grating, different wavelengths of light (different colors is we talk about the visible spectrum) will pass through the grating at different angles.
