A medical treatment where the individual breathes in pure oxygen while in a pressurized room or through a tube. This increased p
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Answer:
Resistivity = 231.481 K Ohm
Yes, Intrinsic Silicon is the semiconductor.
Explanation:
Solution:
At 300K:
Let suppose mobility of electron in intrinsic semiconductor =
Mobility of electron in intrinsic semiconductor is:
= 1300
/volt.sec
Let suppose mobility of hole in intrinsic semiconductor =
= 500
/volt.sec
We know that, intrinsic silicon semiconductor has equal number of holes and electrons. So,
At 300 K
Intrinsic Carrier Concentration = 1.5 x /
= C
And,
Conductivity of intrinsic Silicon is:
σ = C x ( +
) e
e = 1.6 x C
So, plugging in the values, we get:
σ = C x ( +
) e
σ = 1.5 x x (500 + 1300) x 1.6 x
σ = 4.32 x
So, now we can find the resistivity.
Resistivity = 1/σ
Resistivity = 1/ 4.32 x
Resistivity = 231.481 K Ohm
Yes, Intrinsic Silicon is the semiconductor.
The time interval for which the proton remains in the field is -
Δt = .
We have a proton entering a uniform magnetic field which is in a direction perpendicular to the proton's velocity.
We have to determine time interval during which the proton is in the field.
<h3>What is the magnitude of force on the charged particle moving in a uniform magnetic field?</h3>The magnitude of force on the charged particle moving in a uniform magnetic field is given by -
F = qvB sinθ
According to the question, we have -
Entering Velocity (v) = 20 i m/s
Magnetic field intensity (B) = 0.3 T
Leaving velocity (u) = - 20 j m/s
Now -
The entering and leaving velocity vectors have 90 degrees difference between them. Therefore, only a quarter of distance of the complete circular path of radius 'R' is traced by the proton. Therefore -
d = =
Since, the radius of circular path is not given, we will assume it R.
Therefore, time for which proton remained in the field is -
t =
Hence, the time interval for which the proton remains in the field is -
Δt =
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Answer:
C. 0.2 Hertz
Explanation:
The frequency of a spring is equal to the reciprocal of the period:
where
f is the frequency
T is the period
For the spring in this problem,
T = 5 s
therefore, the frequency is