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matrenka [14]
3 years ago
8

If the sprinter accelerates at that rate for a distance of 15 m, and then maintains the velocity he has at that point for the re

mainder of the 100-m dash, what will be his time for the entire race?
Physics
1 answer:
ahrayia [7]3 years ago
4 0

Answer:

The time for the entire race is 11.39 sec.

Explanation:

Given that,

Distance = 15 m

Remainder distance = 100 m

Suppose A sprinter begins a race with an acceleration of 3.4 m/s².

We need to calculate the time

Using equation of motion

s=ut+\dfrac{1}{2}at^2

Put the value in the equation

15=0+\dfrac{1}{2}\times3.4\times t^2

t^2=\dfrac{30}{3.4}

t=2.97\ sec

We need to calculate the final velocity of sprinter

Using equation of motion again

v=u+at

Put the value into the formula

v=0+3.4\times2.97

v=10.09\ m/s

We need to calculate the distance covers by sprinter

d=100-15=85\ m

The sprinter need to covers only 85 m.

We need to calculate the time

Using formula of time

t=\dfrac{d}{v}

Put the value into the formula

t'=\dfrac{85}{10.09}

t'=8.42\ sec

We need to calculate the time for the entire race

t''=t+t'

Put the value into the formula

t''=2.97+8.42

t''=11.39\ sec

Hence, The time for the entire race is 11.39 sec.

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A uniform rod of mass 1.90 kg and length 2.00 m is capable of rotating about an axis passing through its centre and perpendicula
astraxan [27]

Complete Question:

A uniform rod of mass 1.90 kg and length 2.00 m is capable of rotating about an axis passing through its center and perpendicular to its length. A mass m1 = 5.40 kgis  attached to one end and a second mass m2 = 2.50 kg is attached to the other end of the rod. Treat the two masses as point particles.

(a) What is the moment of inertia of the system?

(b) If the rod rotates with an angular speed of 2.70 rad/s, how much kinetic energy does the system have?

(c) Now consider the rod to be of negligible mass. What is the moment of inertia of the rod and masses combined?

(d) If the rod is of negligible mass, what is the kinetic energy when the angular speed is 2.70 rad/s?

Answer:

a) 8.53 kg*m² b) 31.1 J c) 7.9 kg*m² d) 28.8 J

Explanation:

a) If we treat to the two masses as point particles, the rotational inertia of each mass will be the product of the mass times the square of the distance to the axis of rotation, which is exactly the half of the length of the rod.

As the mass has not negligible mass, we need to add the rotational inertia of the rod regarding an axis passing through its centre, and perpendicular to its length.

The total rotational inertia will be as follows:

I = M*L²/12 + m₁*r₁² + m₂*r₂²

⇒ I =( 1.9kg*(2.00)²m²/12) + 5.40 kg*(1.00)²m² + 2.50 kg*(1.00)m²

⇒ I =  8.53 kg*m²

b)  The rotational kinetic energy of the rigid body composed by the rod and  the point masses m₁ and m₂, can be expressed as follows:

Krot = 1/2*I*ω²

if ω= 2.70 rad/sec, and I = 8.53 kg*m², we can calculate Krot as follows:

Krot = 1/2*(8.53 kg*m²)*(2.70)²(rad/sec)²

⇒ Krot = 31.1 J

c) If the mass of the rod is negligible, we can remove its influence of the rotational inertia, as follows:

I = m₁*r₁² + m₂*r₂² = 5.40 kg*(1.00)²m² + 2.50 kg*(1.00)m²

I = 7.90 kg*m²

d) The new rotational kinetic energy will be as follows:

Krot = 1/2*I*ω² = 1/2*(7.9 kg*m²)*(2.70)²(rad/sec)²

Krot= 28.8 J

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Answer:

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Define wavelength as it relates to the electromagnetic spectrum.
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The _____ deflects these winds to the right in the northern hemisphere and to the Southern Hemisphere
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Answer:

Coriolis Effect

Explanation:

The Coriolis effect is responsible for the deflection of winds to the right in the Northern hemisphere and to the right in the Southern hemisphere. It is an effect that occurs because of the rotation of the earth around its axis.

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a person was using a spanner to loosen a tight nut.Their mass was 50kg the spanner was 0.5m long i) what is the persons weight?
sineoko [7]

1) Weight of the person: 490 N

2) Maximum torque: 245 Nm

Explanation:

1)

The weight of a body is equal to the gravitational force exerted on the body; it is given by the equation

F=mg

where

m is the mass of the body

g is the acceleration due to gravity

For the person in this problem,

m = 50 kg is the mass

g=9.8 m/s^2 is the acceleration due to gravity on Earth's surface

Therefore, the weight of the person is

F=(50)(9.8)=490 N

2)

The turning force (also called torque) exerted by a force rotating an object is given by

\tau = Fd sin \theta

where

F is the magnitude of the force

d is the length of the arm (the distance between the force and the pivotal point)

\theta is the angle between the direction of the force and the arm

For the spanner in this problem,

F = 490 N is the force applied (the weight of the person)

d = 0.5 m is the arm (the length of the spanner)

The maximum torque is obtained when \theta=90^{\circ}, therefore it is:

\tau=(490)(0.5)(sin 90^{\circ})=245 N\cdot m

Learn more about weight:

brainly.com/question/8459017

brainly.com/question/11292757

brainly.com/question/12978926

About torque:

brainly.com/question/5352966

#LearnwithBrainly

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3 years ago
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