It is medium loud because very loud is called forte.
mezzo means medium. forte means loud. mezzo forte means medium loud.
answer: d) medium loud
Answer:
T = 4.42 10⁴ N
Explanation:
this is a problem of standing waves, let's start with the open tube, to calculate the wavelength
λ = 4L / n n = 1, 3, 5, ... (2n-1)
How the third resonance is excited
m = 3
L = 192 cm = 1.92 m
λ = 4 1.92 / 3
λ = 2.56 m
As in the resonant processes, the frequency is maintained until you look for the frequency in this tube, with the speed ratio
v = λ f
f = v / λ
f = 343 / 2.56
f = 133.98 Hz
Now he works with the rope, which oscillates in its second mode m = 2 and has a length of L = 37 cm = 0.37 m
The expression for standing waves on a string is
λ = 2L / n
λ = 2 0.37 / 2
λ = 0.37 m
The speed of the wave is
v = λ f
As we have some resonance processes between the string and the tube the frequency is the same
v = 0.37 133.98
v = 49.57 m / s
Let's use the relationship of the speed of the wave with the properties of the string
v = √ T /μ
T = v² μ
T = 49.57² 18
T = 4.42 10⁴ N
Let <em>v</em> be the dog's initial velocity. Then
(13.5 m/s)^2 - <em>v</em> ^2 = 2 (1.50 m/s^2) (49.3 m)
==> <em>v</em> ^2 = (13.5 m/s)^2 - 2 (1.50 m/s^2) (49.3 m)
==> <em>v</em> = √((13.5 m/s)^2 - 2 (1.50 m/s^2) (49.3 m))
==> <em>v</em> ≈ 5.86 m/s
Use the equation Vf=Vi+(A)(t)
since you're trying to find the initial velocity, rearrange the equation to say Vi=Vf-(A)(t)
so, Vi=230-(42)x(2.5)
final answer: Vi=125m/s
Displacement vector that is 8 im magnitude