It does take on new set of proerties
Answer:
Forms over water, warm humid air mass, it's a polar air mass
Explanation: I think that's right sorry if it's not..
GL! :)
Answer: Heyyyyyyyyyyyyyy
here you goo
"<u>some of the effects of urbanization</u>"
<em>Poor air and water quality, insufficient water availability, waste-disposal problems, and high energy consumption are exacerbated by the increasing population density and demands of urban environments</em>
<u><em>"hope this helps"</em></u>
Answer:
13.0186g/mole
63.0326g/mole
Explanation:
Given parameters;
Compounds - CH
CH₃O₃
To solve this problem, let us delve a bit into molar mass of a substance;
The molar mass of a substance (atom or molecule or compound) is the mass in grams of one mole of the substance.
Simply add the component atomic masses to find this number;
Atomic mass of Carbon = 12.0107g/mole
Hydrogen = 1.0079g/mole
Oxygen = 15.9994g/mole
Molar mass of CH = 12.0107 + 1.0079 = 13.0186g/mole
Molar mass of CH₃O₃ = 12.0107 + 3(1.0079) + 3( 15.9994) = 63.0326g/mole
Answer:
2.4*10^-17 J
Explanation:
E = V/d = 300 V / 3*10^-3 m = 1.0*10^5 V/m
Voltage at midpoint = E*d = 1.0*10^5 V/m * 1.5*10^-3 m = 150 V
ΔV = 300 V - 150 V = 150 V
Charge of a proton = 1.6*10^-16 C
U = qΔV = (1.6*10^-16 C)(150V) = 2.4*10^-17 J